A New Analysis of Plane Geometry Finite And Differential With Numerous Example
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In our eReader you can find the full English version of the book. Read A New Analysis of Plane Geometry Finite And Differential With Numerous Example Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book A New Analysis of Plane Geometry Finite And Differential With Numerous Example
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To quickly assess the difficulty of the text, read a short excerpt:
T. G.
34 MEASURES CONTAINING EQUATIONAL ELEMENTS [ill §35. Ill the case in which 2^, = the foregoing results break down. We shall consider this case.
From the equation 2^, (K)+25. Cos(^y3, ) = 0, subtract '$A, . {^c), where c is an arbitrary point. We get %A, \{a, c)\ sin (a^c^) + SB, cos (/3, ^) = 0.
Let 7 be any line, and let (^7) = 6.
Then tA, \(a, c) \ sin {(a, C7) - 6] + ^B, cos {{/3, . Y) - 0] = 0.
Hence l. A;. [(a, . C7) cos 6 - sin {a, . C'y„)\ + S5, {cos (/3, 7) cos + sin (^, y) sin 0\... = 0.
Hence {XA, {a, ry) + IB, cos (/3, 7)} cos = {lA, {a, y. ) - 25, sin (0, y)} sin 0, giving independent of the particular line chosen. Hence the equation represents a direction.
§ 36. To reduce {■^AX^a, ) + tB, cos{ll3, ) = 0y), tvhen 2^, = 0.
We have from § 35 tan {tA, (^a, ) + 25, cos (^5, ) = 07) ^ 2^, (a, 7)+25, cos(/3, 7) tA, {a, ry„) - tB, sin (/3, 7) ' § 37. Examples.
1. Shew that SSOj-^gSin (a, /3j) 2a, sin Oa, ) Now sm (Sa^ (^o?-) + a = /3) = -7 - -^^, V 2''/, ^ + 22a, ag cos (a, ag) .
What to read after A New Analysis of Plane Geometry Finite And Differential With Numerous Example?
You can find similar books in the "Read Also" column, or choose other free books by A W H Ansle William Haughton Thompson to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
T. G.
34 MEASURES CONTAINING EQUATIONAL ELEMENTS [ill §35. Ill the case in which 2^, = the foregoing results break down. We shall consider this case.
From the equation 2^, (K)+25. Cos(^y3, ) = 0, subtract '$A, . {^c), where c is an arbitrary point. We get %A, \{a, c)\ sin (a^c^) + SB, cos (/3, ^) = 0.
Let 7 be any line, and let (^7) = 6.
Then tA, \(a, c) \ sin {(a, C7) - 6] + ^B, cos {{/3, . Y) - 0] = 0.
Hence l. A;. [(a, . C7) cos 6 - sin {a, . C'y„)\ + S5, {cos (/3, 7) cos + sin (^, y) sin 0\... = 0.
Hence {XA, {a, ry) + IB, cos (/3, 7)} cos = {lA, {a, y. ) - 25, sin (0, y)} sin 0, giving independent of the particular line chosen. Hence the equation represents a direction.
§ 36. To reduce {■^AX^a, ) + tB, cos{ll3, ) = 0y), tvhen 2^, = 0.
We have from § 35 tan {tA, (^a, ) + 25, cos (^5, ) = 07) ^ 2^, (a, 7)+25, cos(/3, 7) tA, {a, ry„) - tB, sin (/3, 7) ' § 37. Examples.
1. Shew that SSOj-^gSin (a, /3j) 2a, sin Oa, ) Now sm (Sa^ (^o?-) + a = /3) = -7 - -^^, V 2''/, ^ + 22a, ag cos (a, ag) .
What to read after A New Analysis of Plane Geometry Finite And Differential With Numerous Example?
You can find similar books in the "Read Also" column, or choose other free books by A W H Ansle William Haughton Thompson to read onlineMoreLess
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