A Short Practical Treatise On Spherical Trigonometry Containing a Few Simple R

Byrne, Oliver

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XSin. D' = Co. Sin. P. XCo. Sin. A. . *. X = Co. Sin. P. XCo. Sin. A.
Or by logarithms, Log. Sin. X =Log. Co. Sin. P. + Log. Co. Sin. A. — Log. R. Log. Sin. X = 9. 7585913+ 9. 8546465—10. Log. Sin. 07' = 9. 6182378 . *. X' = M° 13' 55", the comple- ment of which is the required angle = 65° 46' 5". 2nd. If the perpendicular be 60°, and the 19 Ian. X = angle opposite the base 30°, require the angle opposite the perpendicular ?
3rd. Require the angle opposite the perpen- dicular, when the angle op...posite the base is = 45°, and the perpendicular 35° ?
Then find x% which is the complement of the hypothenuse.
R. XSin. A. = Tan. X 'XTan. P.
R. XSin. A. T rp, — ^ ^r — or Log. Ian.
Ian. 1. ° cf'^Log. R. + Log. Sin. A.
— Log. Tan. P. Log. Tan.
x= 10. + 9. 8441979—10.
1547732. Log. Tan. A?' = 9. 6854247. '. /=26 2'53".
Then from 90° 0' 0' Take 26° 2' 53" 63° 57' 7" = the hypothenuse.
2. Given the perpendicular = 98°, and the angle opposite the base = 32°, to find the hypo- thenuse.

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