A Short Practical Treatise On Spherical Trigonometry Containing a Few Simple R
A Short Practical Treatise On Spherical Trigonometry Containing a Few Simple R
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In our eReader you can find the full English version of the book. Read A Short Practical Treatise On Spherical Trigonometry Containing a Few Simple R Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book A Short Practical Treatise On Spherical Trigonometry Containing a Few Simple R
What reading level is A Short Practical Treatise On Spherical Trigonometry Containing a Few Simple R book?
To quickly assess the difficulty of the text, read a short excerpt:
XSin. D' = Co. Sin. P. XCo. Sin. A. . *. X = Co. Sin. P. XCo. Sin. A.
Or by logarithms, Log. Sin. X =Log. Co. Sin. P. + Log. Co. Sin. A. — Log. R. Log. Sin. X = 9. 7585913+ 9. 8546465—10. Log. Sin. 07' = 9. 6182378 . *. X' = M° 13' 55", the comple- ment of which is the required angle = 65° 46' 5". 2nd. If the perpendicular be 60°, and the 19 Ian. X = angle opposite the base 30°, require the angle opposite the perpendicular ?
3rd. Require the angle opposite the perpen- dicular, when the angle op...posite the base is = 45°, and the perpendicular 35° ?
Then find x% which is the complement of the hypothenuse.
R. XSin. A. = Tan. X 'XTan. P.
R. XSin. A. T rp, — ^ ^r — or Log. Ian.
Ian. 1. ° cf'^Log. R. + Log. Sin. A.
— Log. Tan. P. Log. Tan.
x= 10. + 9. 8441979—10.
1547732. Log. Tan. A?' = 9. 6854247. '. /=26 2'53".
Then from 90° 0' 0' Take 26° 2' 53" 63° 57' 7" = the hypothenuse.
2. Given the perpendicular = 98°, and the angle opposite the base = 32°, to find the hypo- thenuse.
What to read after A Short Practical Treatise On Spherical Trigonometry Containing a Few Simple R?
You can find similar books in the "Read Also" column, or choose other free books by Byrne, Oliver to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
XSin. D' = Co. Sin. P. XCo. Sin. A. . *. X = Co. Sin. P. XCo. Sin. A.
Or by logarithms, Log. Sin. X =Log. Co. Sin. P. + Log. Co. Sin. A. — Log. R. Log. Sin. X = 9. 7585913+ 9. 8546465—10. Log. Sin. 07' = 9. 6182378 . *. X' = M° 13' 55", the comple- ment of which is the required angle = 65° 46' 5". 2nd. If the perpendicular be 60°, and the 19 Ian. X = angle opposite the base 30°, require the angle opposite the perpendicular ?
3rd. Require the angle opposite the perpen- dicular, when the angle op...posite the base is = 45°, and the perpendicular 35° ?
Then find x% which is the complement of the hypothenuse.
R. XSin. A. = Tan. X 'XTan. P.
R. XSin. A. T rp, — ^ ^r — or Log. Ian.
Ian. 1. ° cf'^Log. R. + Log. Sin. A.
— Log. Tan. P. Log. Tan.
x= 10. + 9. 8441979—10.
1547732. Log. Tan. A?' = 9. 6854247. '. /=26 2'53".
Then from 90° 0' 0' Take 26° 2' 53" 63° 57' 7" = the hypothenuse.
2. Given the perpendicular = 98°, and the angle opposite the base = 32°, to find the hypo- thenuse.
What to read after A Short Practical Treatise On Spherical Trigonometry Containing a Few Simple R?
You can find similar books in the "Read Also" column, or choose other free books by Byrne, Oliver to read onlineMoreLess
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