A Study of Gas Calorimeters
A Study of Gas Calorimeters
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Hence 0.024 + 0.08 = 0.104 cu. ft. vapor axe brought in for every cu. ft. of saturated c^.s burned. 0.104 cu. ft. at 70^ is equivalent to .104 x 490 . 0.0962 cu. ft. at 32^F.
1 cu. ft. of vapor at 32°P = 0.805 oz. = 22.79 grams.
Digitized by Google Digitized by Google 55 For every cu. ft. of dry g?.s burned there is formed by combustion 0.875 cu. ft. vapor at 70°P 77hich is equivalent to 0.813 Cu. ft., or 0.654 o'z. at 32®P.
The f olloT^inf- computa.tion will show the method employed in all the... following cases.
In tests 1 to 4 the exit temperature = 45.9®E and the volurr.e of the dry products of combustion of 1 cu. ft.
gas with 14^ excess of q.ir = 4.99 cu. ft. The products leave saturated, and the vapor tension at 45.9®P is 0.30 in. mercury, the barometer reading 28.70 inches, and hence the saturated products had a volume- of 4.99 x 28.70 = 28.70 - 0.30 5.05 cu. ft. 5.05 - 4.99 = 0.06 cu. ft. vapor taken out.
But 0.0962 cu. ft. are broi;ight in at 32°P, ^/hich is equiva- lent to 0.099 cu.
What to read after A Study of Gas Calorimeters?
You can find similar books in the "Read Also" column, or choose other free books by Kowalke, Otto Louis, 1878- to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Hence 0.024 + 0.08 = 0.104 cu. ft. vapor axe brought in for every cu. ft. of saturated c^.s burned. 0.104 cu. ft. at 70^ is equivalent to .104 x 490 . 0.0962 cu. ft. at 32^F.
1 cu. ft. of vapor at 32°P = 0.805 oz. = 22.79 grams.
Digitized by Google Digitized by Google 55 For every cu. ft. of dry g?.s burned there is formed by combustion 0.875 cu. ft. vapor at 70°P 77hich is equivalent to 0.813 Cu. ft., or 0.654 o'z. at 32®P.
The f olloT^inf- computa.tion will show the method employed in all the... following cases.
In tests 1 to 4 the exit temperature = 45.9®E and the volurr.e of the dry products of combustion of 1 cu. ft.
gas with 14^ excess of q.ir = 4.99 cu. ft. The products leave saturated, and the vapor tension at 45.9®P is 0.30 in. mercury, the barometer reading 28.70 inches, and hence the saturated products had a volume- of 4.99 x 28.70 = 28.70 - 0.30 5.05 cu. ft. 5.05 - 4.99 = 0.06 cu. ft. vapor taken out.
But 0.0962 cu. ft. are broi;ight in at 32°P, ^/hich is equiva- lent to 0.099 cu.
What to read after A Study of Gas Calorimeters?
You can find similar books in the "Read Also" column, or choose other free books by Kowalke, Otto Louis, 1878- to read onlineMoreLess
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