Algebraic Analysis Solutions And Exercises Illustrating the Fundamental Theor

Cover Algebraic Analysis Solutions And Exercises Illustrating the Fundamental Theor
Algebraic Analysis Solutions And Exercises Illustrating the Fundamental Theor
George Albert Wentworth
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35a;'^— Ga'^r*^— 9a\ 17. 2a'-a'Z)-a^' + 2Z)l 24. A' ^)2+ 2 a^c^— a' c^- 5^ cl 18. 5'"* + Z)''" — 2. 25. Arn?--ah'' + h''m — m\ 19. Y^"— 23/'"2"— 2?/V"+c'^ 26. I— 6a2 + 27a^ 27. (:i'-3/7 + (l-n^ + y)Cr-y)2;-2l 28. 24m' — 28m'n + 6mn' — TtiI 29. Rr'"+" + :^;"3/'* + a:"*3/"' + 3/"'+^ 30. Rr'* + 207^2/ — o^o(^-{- x^'if' — 2aa;3/^ — y*.
Application' OF the Theory of Divisors. § 24. By Theorem I. We prove that x^ — a"^ is divisible by a; — a always^ x^ — a" is divisible by :^ + a when n is even^ x"^
...+ a** is divisible by rr + a when 9^ is odd.
By actual division we find in the above cases : ^— !^ r= x''-' + x^-'a + + m"-' + a«-^ (1) 5!+_^ = :r"-^ - x^'-'a + - xa""-' + a""^ (3) Examples.
1. Resolve into factors x^ — y'.
Here x — y is one factor, and by (1) the other is x' + xy + y''.
106 FACTOEING.
2. Resolve a^ + (b — cf.
Here a + (^ — (?) is one factor, and by (3) tlie other is a'-a(b-c) + (h-c)\ 3. Resolve rr^^+1024y^^ This equals (x^f -\-[(2yyY, one factor of which is x^ -{- (2y)^ and by (3) the other factor is (xj - ixy{4:2/) + (xji^yj - x\AyJ + (Aff = x'' - 4:x'y' + IQx'y' - 64.


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