Alternating Current Machines
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In our eReader you can find the full English version of the book. Read Alternating Current Machines Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Alternating Current Machines
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To quickly assess the difficulty of the text, read a short excerpt:
, ,. , 1000 P D 2000 PKJL.^ Line drop = Ex = R = ^S~^ Section of conductor = S = ^ K^ L 308 ALTERNATING-CURRENT MACHINES.
The total annual charge due to line loss plus interest on conductors is cfx + 2 p&KzLiS, and per delivered kilowatt is c^Px + 2 p, c 2 K, L, S ~ ~ P -Px Substituting the value of S, this becomes or _gg_ftc. :. :. 4 V LOOP. () 9 i - x E 2 x (i - x) If K is substituted for p^K t K t 4 i, 2 1000, then c, ar K 9 = 7^^ + > (i - *j ' (4) To find the minimum value of q, its derivat...ive is placed equal to zero, and there obtains dq 2 K K = V 2 +r*- 2 =o; (5) whence * = - -- - + - . 2 ti * ^ But as jc is positive If the preceding were worked out for a constant or fixed delivered E. M. F. , instead of a fixed impressed E. M. F. , allowing the latter to become what it might, the expression POWER TRANSMISSION. 309 for q would be the same, except that the denominator would be P instead of P (i x), the quantities E, x, P, etc. , being then delivered quantities instead of impressed quantities.
What to read after Alternating Current Machines?
You can find similar books in the "Read Also" column, or choose other free books by Samuel Sheldon to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
, ,. , 1000 P D 2000 PKJL.^ Line drop = Ex = R = ^S~^ Section of conductor = S = ^ K^ L 308 ALTERNATING-CURRENT MACHINES.
The total annual charge due to line loss plus interest on conductors is cfx + 2 p&KzLiS, and per delivered kilowatt is c^Px + 2 p, c 2 K, L, S ~ ~ P -Px Substituting the value of S, this becomes or _gg_ftc. :. :. 4 V LOOP. () 9 i - x E 2 x (i - x) If K is substituted for p^K t K t 4 i, 2 1000, then c, ar K 9 = 7^^ + > (i - *j ' (4) To find the minimum value of q, its derivat...ive is placed equal to zero, and there obtains dq 2 K K = V 2 +r*- 2 =o; (5) whence * = - -- - + - . 2 ti * ^ But as jc is positive If the preceding were worked out for a constant or fixed delivered E. M. F. , instead of a fixed impressed E. M. F. , allowing the latter to become what it might, the expression POWER TRANSMISSION. 309 for q would be the same, except that the denominator would be P instead of P (i x), the quantities E, x, P, etc. , being then delivered quantities instead of impressed quantities.
What to read after Alternating Current Machines?
You can find similar books in the "Read Also" column, or choose other free books by Samuel Sheldon to read onlineMoreLess
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