An Investigation of the Thermal Losses At the Boiler Resulting From the Improper Mixture of the Combustible Gases
An Investigation of the Thermal Losses At the Boiler Resulting From the Improper Mixture of the Combustible Gases
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In our eReader you can find the full English version of the book. Read An Investigation of the Thermal Losses At the Boiler Resulting From the Improper Mixture of the Combustible Gases Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book An Investigation of the Thermal Losses At the Boiler Resulting From the Improper Mixture of the Combustible Gases
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To quickly assess the difficulty of the text, read a short excerpt:
C0 2 =9.3# = 10.82» 00 := .09" N = 79.79* 16 12 1.97 grans 1.43 « 1.25 " Di !
Google Digitized by Google -10- To'find the number of pounds of air used per pound of ooal, first find tile number of grams of each constituent in one hundred liters of the flue gas and from this the weight of carbon and the weight of oxygen.
4.08X1.97= 7.998 grams OOg 9.8x1.97=18.32 grams 00 2 But 32/44 ( °3 )ia oxygen (co£T^ 32/44X7.998 grams- 6.81 grams 32/44X18.82=13.3 grs.O 7.998— 6.91 «= 2.188 grams carbon 18.32...—18.3 ;= 5.02 ■ oarhon From the analysis the weight of free oxygen is, 13.88 X 1.43=19.68 grams 10.82 X 1.43=16.46 grs.O The weight of carbon and oxygen In the 00 is, 3.31 X 1.26 = 4.13 grams 00 .9. X 1.26= 1.125 grs.00 Bu t 18 (0 ) is oxygen.
28 (00) 18/28x4.13 = 2.36 grams oxygen 18/28 Xl« 126=. 644 grs.O 4.13 — 2.36=1.78 grams oarhon 1.126 — .644=; 481 grs. C.
Adding the quantities of Oarhon together and the quantities of oxygen together Oxygen Oarhon Oxygen Oarhon 6.81 2.18 13.2 6.02 19.66 1.78 16.46 .481 2.36 »644 27.72 grams 3.96 grams 0.
What to read after An Investigation of the Thermal Losses At the Boiler Resulting From the Improper Mixture of the Combustible Gases?
You can find similar books in the "Read Also" column, or choose other free books by Williams, Charles Henry to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
C0 2 =9.3# = 10.82» 00 := .09" N = 79.79* 16 12 1.97 grans 1.43 « 1.25 " Di !
Google Digitized by Google -10- To'find the number of pounds of air used per pound of ooal, first find tile number of grams of each constituent in one hundred liters of the flue gas and from this the weight of carbon and the weight of oxygen.
4.08X1.97= 7.998 grams OOg 9.8x1.97=18.32 grams 00 2 But 32/44 ( °3 )ia oxygen (co£T^ 32/44X7.998 grams- 6.81 grams 32/44X18.82=13.3 grs.O 7.998— 6.91 «= 2.188 grams carbon 18.32...—18.3 ;= 5.02 ■ oarhon From the analysis the weight of free oxygen is, 13.88 X 1.43=19.68 grams 10.82 X 1.43=16.46 grs.O The weight of carbon and oxygen In the 00 is, 3.31 X 1.26 = 4.13 grams 00 .9. X 1.26= 1.125 grs.00 Bu t 18 (0 ) is oxygen.
28 (00) 18/28x4.13 = 2.36 grams oxygen 18/28 Xl« 126=. 644 grs.O 4.13 — 2.36=1.78 grams oarhon 1.126 — .644=; 481 grs. C.
Adding the quantities of Oarhon together and the quantities of oxygen together Oxygen Oarhon Oxygen Oarhon 6.81 2.18 13.2 6.02 19.66 1.78 16.46 .481 2.36 »644 27.72 grams 3.96 grams 0.
What to read after An Investigation of the Thermal Losses At the Boiler Resulting From the Improper Mixture of the Combustible Gases?
You can find similar books in the "Read Also" column, or choose other free books by Williams, Charles Henry to read onlineMoreLess
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