Applied Mechanics

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From equa- tion (2), Art. 83, 200 = 56.56 1 + 16.1 1\ t = 2.18 sec.
Since the horizontal velocity is constant the horizontal distance traveled in 2.18 seconds is xi = 56.56 X2.18 = 123.4 ft.
Problem 1. A shot is fired at an angle of 60° with the horizontal, with a velocity of 500 feet per second. Find the height and the range.
Ans. ;» = 2911 ft. d = 6725 ft.
Problem 2. What is the maximum height and the maximum range theo- retically possible for a projectile with a muzzle velocity of 2000 feet
...per second?
Ans. h = 11.78 miles, d = 23.56 miles.
Problem 3. A gun with a barrel 3 feet long shoots a bullet with a muzzle velocity of 600 feet per second. When shooting at a target 1000 feet distant, to what height should the rear sight be raised? Ans. 1.615 inches.
152 APPLIED MECHANICS [Chapvih GENERAL PROBLEMS.
Problem 1. A 10-pound weight at the end of a 3-foot cord revolves about a vertical axis as a conical pendulum. What is the tension in the cord and the speed of rotation if 9 = 30"?


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