Chemical Reactions And Their Equations
Chemical Reactions And Their Equations
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In other words, the permanganate (Mn0 4 ~) can be any soluble per- manganate, either of sodium, potassium, etc. ; the ferrous salt can be any soluble salt, either sulfate, chloride, nitrate, etc. ; and the acid can be either HC1, H 2 SO 4, HNO 3, etc.
Problem 2. A nitrite solution is oxidized to a nitrate solution by an acidified bichromate solution : First, the valence numbers are written under the ions NO 2 - - +- Cr, O 7 - = N0 3 - - f 2Cr+++ 3 2(6) 5 2(3) = 12 j = 6 The nitrogen of the nitr...ite therefore has been oxidized from 3 to 5 increased 2 steps. The chromium of the chromate has been reduced from 12 to 6 decreased 6 44 CHEMICAL REACTIONS AND THEIR EQUATIONS steps. To balance the factors are reversed, 6(2) = 2(6), therefore, 6NO 2 ~ + 2Cr 2 O 7 = 6NO 3 - + 4Cr+++ The proportion 6 : 2 can in this case be simplified to 3 : 1 and the unfinished equation becomes: 3NO 2 - + O 2 O 7 = 3NO 3 - + 2Cr+++ Second, the charges are counted on both sides, thus on the left there are 3 nitrites = 3 negative charges 1 bichromate = 2 negative charges a total of 5 negative charges on the right there are 3 nitrates = 3 negative charges 2 chromic ions = 6 positive charges a total of 3 positive charges To balance +3 and 5 requires either 8 positive charges to the left, or 8 negative charges to the right.
What to read after Chemical Reactions And Their Equations?
You can find similar books in the "Read Also" column, or choose other free books by Ingo W D Ingo Waldemar Dagobert Hackh to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
In other words, the permanganate (Mn0 4 ~) can be any soluble per- manganate, either of sodium, potassium, etc. ; the ferrous salt can be any soluble salt, either sulfate, chloride, nitrate, etc. ; and the acid can be either HC1, H 2 SO 4, HNO 3, etc.
Problem 2. A nitrite solution is oxidized to a nitrate solution by an acidified bichromate solution : First, the valence numbers are written under the ions NO 2 - - +- Cr, O 7 - = N0 3 - - f 2Cr+++ 3 2(6) 5 2(3) = 12 j = 6 The nitrogen of the nitr...ite therefore has been oxidized from 3 to 5 increased 2 steps. The chromium of the chromate has been reduced from 12 to 6 decreased 6 44 CHEMICAL REACTIONS AND THEIR EQUATIONS steps. To balance the factors are reversed, 6(2) = 2(6), therefore, 6NO 2 ~ + 2Cr 2 O 7 = 6NO 3 - + 4Cr+++ The proportion 6 : 2 can in this case be simplified to 3 : 1 and the unfinished equation becomes: 3NO 2 - + O 2 O 7 = 3NO 3 - + 2Cr+++ Second, the charges are counted on both sides, thus on the left there are 3 nitrites = 3 negative charges 1 bichromate = 2 negative charges a total of 5 negative charges on the right there are 3 nitrates = 3 negative charges 2 chromic ions = 6 positive charges a total of 3 positive charges To balance +3 and 5 requires either 8 positive charges to the left, or 8 negative charges to the right.
What to read after Chemical Reactions And Their Equations?
You can find similar books in the "Read Also" column, or choose other free books by Ingo W D Ingo Waldemar Dagobert Hackh to read onlineMoreLess
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