Concrete And Reinforced Concrete a Condensed Practical Treatise On the Problems
Concrete And Reinforced Concrete a Condensed Practical Treatise On the Problems
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68. Assume that &' equals fourteen times the slab thickness, or 70 inches. (See page 90. ) Substituting these values in the upper part of Equation (12) in order to find the value of c, we find that c = 390 pounds per square inch. Substituting the known values in the second half of Equation (12), to obtain a more precise value of s, we find that s = 15, 734 pounds per square inch.
The required area (3. 43 square inches) of the bars will be afforded by six i-inch round bars (6 X . 60 = 3. 60) wit...h consid- erable to spare. From Table XVIII we find that six 1-inch bars, either square or round, if placed in one row, would require a beam 14. 72 inches wide. This is undesirably wide, and so we shall use two rows, three in each row, and make the beam 9 inches wide. This will add an inch to the depth, and the total depth will be 22 + 3 = 25 inches. The concrete below the slab is therefore 9 inches wide by 20 inches deep, instead of 12 inches wide by 15 inches deep, as assumed when computing the dead load, but the weight is the same.
What to read after Concrete And Reinforced Concrete a Condensed Practical Treatise On the Problems?
You can find similar books in the "Read Also" column, or choose other free books by Webb, Walter Loring, 1863-1941 to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
68. Assume that &' equals fourteen times the slab thickness, or 70 inches. (See page 90. ) Substituting these values in the upper part of Equation (12) in order to find the value of c, we find that c = 390 pounds per square inch. Substituting the known values in the second half of Equation (12), to obtain a more precise value of s, we find that s = 15, 734 pounds per square inch.
The required area (3. 43 square inches) of the bars will be afforded by six i-inch round bars (6 X . 60 = 3. 60) wit...h consid- erable to spare. From Table XVIII we find that six 1-inch bars, either square or round, if placed in one row, would require a beam 14. 72 inches wide. This is undesirably wide, and so we shall use two rows, three in each row, and make the beam 9 inches wide. This will add an inch to the depth, and the total depth will be 22 + 3 = 25 inches. The concrete below the slab is therefore 9 inches wide by 20 inches deep, instead of 12 inches wide by 15 inches deep, as assumed when computing the dead load, but the weight is the same.
What to read after Concrete And Reinforced Concrete a Condensed Practical Treatise On the Problems?
You can find similar books in the "Read Also" column, or choose other free books by Webb, Walter Loring, 1863-1941 to read onlineMoreLess
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