Differential And Integral Calculus for Technical Schools And Colleges

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Planes perpendicular to the X-axis at intervals Ax divide the solid into laminae LL'; planes perpendicular to the y-axis at intervals A?/ divide these laminae into prisms FP'; planes perpendicular to the Z-axis at intervals Aa divide these prisms into elements of volume aa'. The volume of aa' = Ax- Ay ■ Az; the volume of PP' = S Ax ■ Ay ■ Az—6 ■ Ax ■ Ay • Az, where 6 is less than unity. When Ax, Ay, Az approach zero, volume of PP' = 2 dx-dy-dz — 6-dx-dy-dz. Since 6 - dx • dy -dz is an infinites...imal of a higher order than 2 dx-dy •dz = PD • dx ■ dy, in the limit of the sum volume of PP =£ dx- dy ■ dz.
The volume of the lamina LL' = 2 PP' ; the volume of the solid is ' x=OA x=OA y = BO F = 2 iL' = 2 2 PP'- X=0 95 = 1^ = Hence in the limit I I dx dy dz.
92 DIFFERENTIAL AND INTEGRAL CALCULUS Example. — Find the volume of the solid bounded by the 2 ^^ ZX-plane, the XF-plane, and the planes x=a,y=b, z=mx.
In this problem I j dxdydz = m\ xdxdy Fio. 33.
: mb £ xdx = ^mba'.


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