Direct And Alternating Current Testing
Direct And Alternating Current Testing
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RI and XI ^ drops for different values of primary current, as in Fig. 7, these curves being straight lines. Compare these curves with the cor- responding curves for an alternator, Fig. 2, Exp. 3-8.
For normal full-load current, mark the value of each drop in volts and as per cent, of normal full-load voltage. The per 5-B] TEST BY LOSSES.
165 cent, impedance drop is also called impedance ratio (13, Exp. 3-B).
30. Curves for Copper Losses. Calculate RI^ 2 for -^ J, ^, f, i and ij load. Plotted as... in Fig. 8, these give the values of 95. 38 121. 9 0. 25 0. 5 0. 75 AMPERES, PRIMARY.
1. 0 FIG. 8. Losses and efficiency of a 2 K. W. Transformer.
the copper loss, including load losses, for different currents; the curve is a parabola.
It is seen that the copper loss, in watts, for a given load is pro- portional to the copper drop, in volts. The copper loss, expressed as a per cent, of rated volt-amperes, is equal to the copper drop, expressed as a per cent, of rated volts.
Per cent, copper loss = RP/EI.
What to read after Direct And Alternating Current Testing?
You can find similar books in the "Read Also" column, or choose other free books by Frederick Bedell to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
RI and XI ^ drops for different values of primary current, as in Fig. 7, these curves being straight lines. Compare these curves with the cor- responding curves for an alternator, Fig. 2, Exp. 3-8.
For normal full-load current, mark the value of each drop in volts and as per cent, of normal full-load voltage. The per 5-B] TEST BY LOSSES.
165 cent, impedance drop is also called impedance ratio (13, Exp. 3-B).
30. Curves for Copper Losses. Calculate RI^ 2 for -^ J, ^, f, i and ij load. Plotted as... in Fig. 8, these give the values of 95. 38 121. 9 0. 25 0. 5 0. 75 AMPERES, PRIMARY.
1. 0 FIG. 8. Losses and efficiency of a 2 K. W. Transformer.
the copper loss, including load losses, for different currents; the curve is a parabola.
It is seen that the copper loss, in watts, for a given load is pro- portional to the copper drop, in volts. The copper loss, expressed as a per cent, of rated volt-amperes, is equal to the copper drop, expressed as a per cent, of rated volts.
Per cent, copper loss = RP/EI.
What to read after Direct And Alternating Current Testing?
You can find similar books in the "Read Also" column, or choose other free books by Frederick Bedell to read onlineMoreLess
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