Electric Light Arithmetic
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In our eReader you can find the full English version of the book. Read Electric Light Arithmetic Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Electric Light Arithmetic
What reading level is Electric Light Arithmetic book?
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Ans. 7-6 Amperes.
Example 3, Three arc lamps in series have a resistance of 9-36 Ohms, while the resistance of the leading wires is ri Ohm and that of the dynamo machine is 2 '8 Ohms. Find what must be the electro-motive force of the machine when the strength of the current produced is I4'8 Amperes.
In this case we have R = 2-8 -f 9-36 + ri = 13-26 Ohms, / = 14-8 Amperes ; and therefore substituting these values in the equation E = /X R it becomes E = 13-26 x 14-8 = 196-3 Volts.
Example 4. A ce...rtain arc lamp has an electrical resistance of 2-5 Ohms, while that of the leading wires is "5 Ohm, and that of the machine 0*5 Ohm. What must be the electro-motive force of the machine so as to send a current of 25 Amperes through three of these lamps and the leading wires ? Ans. 213 Volts nearly.
ELECTRIC LIGHT ARITHMETIC. 23 Example 5. Calculate from the following data the average resistance of each of three arc lamps which are arranged in series. The electro-motive force of the machine is 244 Volts and its resistance is 37 Ohms, while that of the leading wires is 2 Ohms, and the strength of current flowing through each lamp is 21 Amperes.
What to read after Electric Light Arithmetic?
You can find similar books in the "Read Also" column, or choose other free books by Richard Evan Day to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Ans. 7-6 Amperes.
Example 3, Three arc lamps in series have a resistance of 9-36 Ohms, while the resistance of the leading wires is ri Ohm and that of the dynamo machine is 2 '8 Ohms. Find what must be the electro-motive force of the machine when the strength of the current produced is I4'8 Amperes.
In this case we have R = 2-8 -f 9-36 + ri = 13-26 Ohms, / = 14-8 Amperes ; and therefore substituting these values in the equation E = /X R it becomes E = 13-26 x 14-8 = 196-3 Volts.
Example 4. A ce...rtain arc lamp has an electrical resistance of 2-5 Ohms, while that of the leading wires is "5 Ohm, and that of the machine 0*5 Ohm. What must be the electro-motive force of the machine so as to send a current of 25 Amperes through three of these lamps and the leading wires ? Ans. 213 Volts nearly.
ELECTRIC LIGHT ARITHMETIC. 23 Example 5. Calculate from the following data the average resistance of each of three arc lamps which are arranged in series. The electro-motive force of the machine is 244 Volts and its resistance is 37 Ohms, while that of the leading wires is 2 Ohms, and the strength of current flowing through each lamp is 21 Amperes.
What to read after Electric Light Arithmetic?
You can find similar books in the "Read Also" column, or choose other free books by Richard Evan Day to read onlineMoreLess
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