Elementary Manual On Applied Mechanics
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In our eReader you can find the full English version of the book. Read Elementary Manual On Applied Mechanics Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Elementary Manual On Applied Mechanics
What reading level is Elementary Manual On Applied Mechanics book?
To quickly assess the difficulty of the text, read a short excerpt:
RT. IiD/iD/. -D/ Or, . . . T^T, :!, :: i : 2' : 3 ::i : 8 : 27.
In -other words, the strengths of the three solid shafts will be as 1:8:27.
A good wrought- iron shaft of i" diameter has been found to withstand a torque of 800 lbs, -ft. , or 9600 Ibs. -inches, which means that they will resist 800 Ibs. Force at i foot, or 12" leverage, or 400 Ibs. At 2 feet, or 24", and so on.
Or, . P x R' = 800 Ibs. -feet of torque i. E. , . P x R" = 9600 Ibs. -inch torque. EXAMPLE II. On the above basis, what ...force acting at the circumference of a pulley 20" diameter will break a wrought- iron shaft 2" diameter?
ANSWER. By the above rule we have the proportion : T I: T, -D^iD/ But Tj - P! x R/' = 800 Ibs x i a" AndT, = P 8 x R 8 " - P, x 10" ... P^: P 2 R, :: J>*:J>f i. E. , P a R a x D^ = P^ x D, 1 P. R. X D, 8 800 x 12" x 8 p . - iy x R, -nr^" ' 76801bs lever or circumference of the pulley, and K the length of the arm or radius of the wheel or pulley.
Consequently, P x E =-J^( ^-D 2 x - \ =f g "- ' W But S is a constant quantity for any particular material.
What to read after Elementary Manual On Applied Mechanics?
You can find similar books in the "Read Also" column, or choose other free books by Andrew Jamieson to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
RT. IiD/iD/. -D/ Or, . . . T^T, :!, :: i : 2' : 3 ::i : 8 : 27.
In -other words, the strengths of the three solid shafts will be as 1:8:27.
A good wrought- iron shaft of i" diameter has been found to withstand a torque of 800 lbs, -ft. , or 9600 Ibs. -inches, which means that they will resist 800 Ibs. Force at i foot, or 12" leverage, or 400 Ibs. At 2 feet, or 24", and so on.
Or, . P x R' = 800 Ibs. -feet of torque i. E. , . P x R" = 9600 Ibs. -inch torque. EXAMPLE II. On the above basis, what ...force acting at the circumference of a pulley 20" diameter will break a wrought- iron shaft 2" diameter?
ANSWER. By the above rule we have the proportion : T I: T, -D^iD/ But Tj - P! x R/' = 800 Ibs x i a" AndT, = P 8 x R 8 " - P, x 10" ... P^: P 2 R, :: J>*:J>f i. E. , P a R a x D^ = P^ x D, 1 P. R. X D, 8 800 x 12" x 8 p . - iy x R, -nr^" ' 76801bs lever or circumference of the pulley, and K the length of the arm or radius of the wheel or pulley.
Consequently, P x E =-J^( ^-D 2 x - \ =f g "- ' W But S is a constant quantity for any particular material.
What to read after Elementary Manual On Applied Mechanics?
You can find similar books in the "Read Also" column, or choose other free books by Andrew Jamieson to read onlineMoreLess
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