Elementary Plane Trigonometry, That Is, Plane Trigonometry Without Imaginaries

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b 2 - a 2 1 - tan (9 , „ „ (1) + (2) gives _^_ = __^ = tan (45 - 0) ^ - to rives ° 2 ~ b2 - 2sin ^ + ^ sin( /> t (2) - (i) gives -—^ _ = tan x> say Now tan 2 U + 6 -) - tan 2 6 - = -JL n (» + g)jm»_ V *' 2 oos 2 f cos 2 (> + £) = tan x tan - see 2 ($ + -\ : tan 2 ( + £) |, _ tan x tan £j = tan 1 jtan f + tan x | ••• ten 2 (* + £)- tan £ tan (f + x ) , , (0 ,c 2 - b 2 i = tan - tan 1-+ tan- 1 ^94 Trigonometry — Chapter XVI Exercises 1. A surveyor has a Gunter's chain, and a logarithmic table-boo...k, but no instrument for measuring angles : show how he can find the distance of an inaccessible object in his own horizontal plane.
2 . At each of two points A, B, on the bank of a river, the join of two points P, Q, on the opposite bank (all four being in the same horizontal plane) subtends the same angle OC ; also the angles QAB, PBA are respectively /3, y ', and QBA is greater than PBA : prove that PQ/AB = sin a/sin (OC + (3 + y) and = {sin (OC + (3) sin (OC + y) — sin /3 sin y}/sin 2 (OC + /3 + y) /.


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