Elementary Practical Mechanics
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In our eReader you can find the full English version of the book. Read Elementary Practical Mechanics Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Elementary Practical Mechanics
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These are the compressions in the support- ing legs.
58. The Arch. — The reactions at the ends and the com- pression in the center of an arch may be found by regarding one half of the arch as a free body. The arrangement of forces shown in Fig. 112 then results, which is that of a simple system of non-concurrent forces. Therefore (1) ff2--ffi=0; (2) F-Tf-TFi, etc.,=0; (3) WXd3 + WiXd2~H2Xd=0.
Loads W, Wi, etc., being known and the dimensions of ELEMENTARY PRACTICAL MECHANICS 105 the arch, these... equations may be readily solved for V and Hi, the end reactions, and H2 the compression at the center of the arch ring.
The end reactions for the other half are the same if the arch is loaded uni- formly, if not similar equa- tions may also be written for the second half. Fig.
113 shows a laboratory model of an arch in which the computed forces may be checked by spring balances. One end only of the arch is left free or " floating " at a time, the other turns freely about a pin through the horizontal frame which serves as a guide to maintain the arch in a vertical position^ Fig.
What to read after Elementary Practical Mechanics?
You can find similar books in the "Read Also" column, or choose other free books by Joseph Moore Jameson to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
These are the compressions in the support- ing legs.
58. The Arch. — The reactions at the ends and the com- pression in the center of an arch may be found by regarding one half of the arch as a free body. The arrangement of forces shown in Fig. 112 then results, which is that of a simple system of non-concurrent forces. Therefore (1) ff2--ffi=0; (2) F-Tf-TFi, etc.,=0; (3) WXd3 + WiXd2~H2Xd=0.
Loads W, Wi, etc., being known and the dimensions of ELEMENTARY PRACTICAL MECHANICS 105 the arch, these... equations may be readily solved for V and Hi, the end reactions, and H2 the compression at the center of the arch ring.
The end reactions for the other half are the same if the arch is loaded uni- formly, if not similar equa- tions may also be written for the second half. Fig.
113 shows a laboratory model of an arch in which the computed forces may be checked by spring balances. One end only of the arch is left free or " floating " at a time, the other turns freely about a pin through the horizontal frame which serves as a guide to maintain the arch in a vertical position^ Fig.
What to read after Elementary Practical Mechanics?
You can find similar books in the "Read Also" column, or choose other free books by Joseph Moore Jameson to read onlineMoreLess
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