Elementary Science Applied to Sanitation And Plumbers
Elementary Science Applied to Sanitation And Plumbers
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In our eReader you can find the full English version of the book. Read Elementary Science Applied to Sanitation And Plumbers Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Elementary Science Applied to Sanitation And Plumbers
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To quickly assess the difficulty of the text, read a short excerpt:
Diameter.
Contents in cubic feet = ITTRS = i. X yX~x|-Xy = 179| cubic feet of air.
(&) Find the weight of a solid copper sphere 1 ft. 2 ins. Diameter. (Sp. Gr. Of copper = 8-79. ) Weight of copper sphere = JTT R 3 x S. G. X Weight of cubic foot of water - A x x ^ x 1 x ^ x !! x f - 457-2 Ibs. (approx. ).
The volume of a segment of a sphere may be found by the following formula : SOLIDS 71 Volume of segment - JTI-H (H 2 + 3R 2 ) R = radius of base of seg- ment.
H = height of ditto.
Example. Find... the number of cubic feet of water contained by a segment of a sphere the diameter of which is 8 ft. And vertical height 2ft.
Contents in gallons = J^rH (H 2 + 3R 2 ) 1 22 _2j/_2_ _2_\ /_3^ _ _4_\\ T X T X T{VT X TJ " VT X T X TVJ 22 22 52 = 7r=-(4 + 48") = ^x-^ = 54-47 cubic feet.
EXAMPLES XXXVI (i. ) Find the volume of a sphere, diameter 20 ins. (ii. ) Find the volume of a sphere, diameter 21 ft. (iii. ) Find the volume of a sphere, diameter 10*5 ins. (iv. ) Find the volume of a sphere, diameter 1-4 ins.
What to read after Elementary Science Applied to Sanitation And Plumbers?
You can find similar books in the "Read Also" column, or choose other free books by A Herring Shaw to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Diameter.
Contents in cubic feet = ITTRS = i. X yX~x|-Xy = 179| cubic feet of air.
(&) Find the weight of a solid copper sphere 1 ft. 2 ins. Diameter. (Sp. Gr. Of copper = 8-79. ) Weight of copper sphere = JTT R 3 x S. G. X Weight of cubic foot of water - A x x ^ x 1 x ^ x !! x f - 457-2 Ibs. (approx. ).
The volume of a segment of a sphere may be found by the following formula : SOLIDS 71 Volume of segment - JTI-H (H 2 + 3R 2 ) R = radius of base of seg- ment.
H = height of ditto.
Example. Find... the number of cubic feet of water contained by a segment of a sphere the diameter of which is 8 ft. And vertical height 2ft.
Contents in gallons = J^rH (H 2 + 3R 2 ) 1 22 _2j/_2_ _2_\ /_3^ _ _4_\\ T X T X T{VT X TJ " VT X T X TVJ 22 22 52 = 7r=-(4 + 48") = ^x-^ = 54-47 cubic feet.
EXAMPLES XXXVI (i. ) Find the volume of a sphere, diameter 20 ins. (ii. ) Find the volume of a sphere, diameter 21 ft. (iii. ) Find the volume of a sphere, diameter 10*5 ins. (iv. ) Find the volume of a sphere, diameter 1-4 ins.
What to read after Elementary Science Applied to Sanitation And Plumbers?
You can find similar books in the "Read Also" column, or choose other free books by A Herring Shaw to read onlineMoreLess
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