Elements of Plane Trigonometry
Elements of Plane Trigonometry
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In our eReader you can find the full English version of the book. Read Elements of Plane Trigonometry Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Elements of Plane Trigonometry
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Long, when lying horizontal supported at its ends, will carry a safe load of 150 lb. On its middle round. Is it safe for a man weighing 190 lb. To mount it when it is so placed as to reach a window 18 ft. Above the ground '?
We have to find the component, perpendicu- lar to the ladder, of the man's weight when he stands on the middle round. Let WP, drawn vertically downward frorn the middle point of AB, Fig. 32, represent 100 (which need not be on the same scale as AB which repre- sents 30). Th...en the component perpendicular to AB is Now by (11) § 12, whence WQ = 190 cos PWQ = 190 cos CAB. Cos CAB = AC/AB = 4/5, WQ = 190 x 4 = 152, which is greater than the safe load.
Example 3. A traveling crane moves with uniform speed down a shop 297 ft. Long and 60 ft. Wide in 1 min. 41 sec. It carries a load from one corner along the diagonal to the opposite corner. Find the speed of the crane and of the car which runs on it.
Let AP = the speed of the load along the diagonal which by the data of the problem = 3 ft.
What to read after Elements of Plane Trigonometry?
You can find similar books in the "Read Also" column, or choose other free books by Alfred Monroe Kenyon to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Long, when lying horizontal supported at its ends, will carry a safe load of 150 lb. On its middle round. Is it safe for a man weighing 190 lb. To mount it when it is so placed as to reach a window 18 ft. Above the ground '?
We have to find the component, perpendicu- lar to the ladder, of the man's weight when he stands on the middle round. Let WP, drawn vertically downward frorn the middle point of AB, Fig. 32, represent 100 (which need not be on the same scale as AB which repre- sents 30). Th...en the component perpendicular to AB is Now by (11) § 12, whence WQ = 190 cos PWQ = 190 cos CAB. Cos CAB = AC/AB = 4/5, WQ = 190 x 4 = 152, which is greater than the safe load.
Example 3. A traveling crane moves with uniform speed down a shop 297 ft. Long and 60 ft. Wide in 1 min. 41 sec. It carries a load from one corner along the diagonal to the opposite corner. Find the speed of the crane and of the car which runs on it.
Let AP = the speed of the load along the diagonal which by the data of the problem = 3 ft.
What to read after Elements of Plane Trigonometry?
You can find similar books in the "Read Also" column, or choose other free books by Alfred Monroe Kenyon to read onlineMoreLess
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