Elements of Synthetic Solid Geometry

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AA', BB 1, etc. , are the diagonals of a ppd. Show that a plane through DBC' cuts off a pyramid which is one-sixth the ppd.
12. The direction edges of a ppd. Are a, b, c, and the angles between them are Z (be) = X, Z (ca) = /u, Z (aft) v. Then the vol. Is abc Y/ { 1 cos 2 X cos 2 /j. Cos 2 v + 2 cos X cos p cos v}. OA, OB, OC are the direction edges; Z COB = X, Z COA = M, ZAOB = v.
Let CP be normal to the plane of A OB, and PQ, PE be J_s upon OA and OB.
vol. Of ppd. = OA- OB sin v CP.
(P. Art.
...215. ) ot OQPR are concyclic, and OP is a diameter of the circumcircle ; (P. Art. 228. ) and But and CT=V(L~ \ sin 2 v) sm v ' vol. = ab -v/( c2 s i n2 * ~ QR 2 )- QR 2 = OO, 2 + OR 2 - '20Q OR cos v ; OQ 2 = c 2 cos 2 fi, and O. R 2 = c 2 cos 2 X.
REGULAR POLYHEDKA. 123 Whence, by substitution, vol. = abc - x /{ 1 cos 2 X cos 2 fj. Cos 2 v + 2 cos X cos p cos v}. 1 13. Show from the character of the result in Ex. 12 that if in fcny ppd. X, /*, v are all acute, all vertices except the one opposite have one acute and two obtuse angles, etc.


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