Experimental Harmonic Motion a Manual for the Laboratory
Experimental Harmonic Motion a Manual for the Laboratory
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In our eReader you can find the full English version of the book. Read Experimental Harmonic Motion a Manual for the Laboratory Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Experimental Harmonic Motion a Manual for the Laboratory
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External diameter =2^ = 5-00 cm. Internal diameter =2r= 0*96 cm.
Hence J/F=Jf (4 2 +i# 2 +|r 2 ) = 1108 x 5-75 = 0-00637 xlO 6 gm. Cm. 2 .
Distance of knife-edge from top of bob = 29'64 cm.
Hence =29-64 + ^ = 33-16 cm.
And- M1 2 = 1 108 x 33'16 2 = 1-2183 x 10 6 gm. Cm. 2 .
Then K 2 = Mb 2 + Ml 2 = 0-00637 X 10 6 4-1-2183 x!0 6 = 1-225 x 10 6 gm. Cm. 2 .
Hence #0 + ^2=2-676 x 10 6 + l'225x 10 6 =3'901 x 10 6 gm. Cm. 2 .
From the vibrations of the loaded pendulum we found #! = 3-907 x 10 6 gm. C...m. 2 . Thus KI differs from K + K 2 by only 0'15 per cent.
EXPERIMENT 10. Determination of "g" by a rigid pendulum.
57. Introduction. In 49 it is shown that the periodic time of a rigid pendulum is given by where K is the moment of inertia of the pendulum about its axis of suspension, h is the distance of the centre of gravity from that axis and M is the mass of the pendulum. It was explained that this equation cannot be used for finding g, since the value of K cannot be satisfactorily found from the mass and dimensions of the pendulum.
What to read after Experimental Harmonic Motion a Manual for the Laboratory?
You can find similar books in the "Read Also" column, or choose other free books by G F C George Frederick Charles Searle to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
External diameter =2^ = 5-00 cm. Internal diameter =2r= 0*96 cm.
Hence J/F=Jf (4 2 +i# 2 +|r 2 ) = 1108 x 5-75 = 0-00637 xlO 6 gm. Cm. 2 .
Distance of knife-edge from top of bob = 29'64 cm.
Hence =29-64 + ^ = 33-16 cm.
And- M1 2 = 1 108 x 33'16 2 = 1-2183 x 10 6 gm. Cm. 2 .
Then K 2 = Mb 2 + Ml 2 = 0-00637 X 10 6 4-1-2183 x!0 6 = 1-225 x 10 6 gm. Cm. 2 .
Hence #0 + ^2=2-676 x 10 6 + l'225x 10 6 =3'901 x 10 6 gm. Cm. 2 .
From the vibrations of the loaded pendulum we found #! = 3-907 x 10 6 gm. C...m. 2 . Thus KI differs from K + K 2 by only 0'15 per cent.
EXPERIMENT 10. Determination of "g" by a rigid pendulum.
57. Introduction. In 49 it is shown that the periodic time of a rigid pendulum is given by where K is the moment of inertia of the pendulum about its axis of suspension, h is the distance of the centre of gravity from that axis and M is the mass of the pendulum. It was explained that this equation cannot be used for finding g, since the value of K cannot be satisfactorily found from the mass and dimensions of the pendulum.
What to read after Experimental Harmonic Motion a Manual for the Laboratory?
You can find similar books in the "Read Also" column, or choose other free books by G F C George Frederick Charles Searle to read onlineMoreLess
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