Fish's Arithmetic Number Two : Oral And Written, Upon the Inductive Method 2
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In our eReader you can find the full English version of the book. Read Fish's Arithmetic Number Two : Oral And Written, Upon the Inductive Method 2 Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Fish's Arithmetic Number Two : Oral And Written, Upon the Inductive Method 2
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ft., there remains a solid whose volume is 63324 cu. ft., Fig. 3. This remainder consists of solids similar to those marked B, C, and D, in Fig, 1 and Fig 2 of Art. 391.
The volume of a rectangular solid is equal to the product of the area of its base by its height or thickness (222) ; hence, if the volume be divided by the area of the base, the quotient will be the thickness. Now since the three equal rectangular solids, each of which is 70 ft. square, and whose thickness is the units' figure ...of the root, contain the greater part of the 62224 cu. ft., 3 x 70^ or 14700, may be used as a trial diviso.' to find the thickness. Dividing 62224 by 14700, the quotient is 4. But this quotient may be too large. To test it, find the volume of Fig. 3, considerine: 4 ft. as the thickness. Thus, 3 x 70' x 4 + 3 x 70 x 4' + 4^ = 62224. Hence, 4 ft. is the triiie thickness, and 74 ft. the length of the edge of a cube whose volume is 405234 cu. ft.
258 evolution: If the cube root contains more than two figures, it may be found by a similar process, as in tlje following example, where it will be seen that the partial divisor at each step is equal to three times the square of that part of the root already found.
What to read after Fish's Arithmetic Number Two : Oral And Written, Upon the Inductive Method 2?
You can find similar books in the "Read Also" column, or choose other free books by Daniel W Fish to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
ft., there remains a solid whose volume is 63324 cu. ft., Fig. 3. This remainder consists of solids similar to those marked B, C, and D, in Fig, 1 and Fig 2 of Art. 391.
The volume of a rectangular solid is equal to the product of the area of its base by its height or thickness (222) ; hence, if the volume be divided by the area of the base, the quotient will be the thickness. Now since the three equal rectangular solids, each of which is 70 ft. square, and whose thickness is the units' figure ...of the root, contain the greater part of the 62224 cu. ft., 3 x 70^ or 14700, may be used as a trial diviso.' to find the thickness. Dividing 62224 by 14700, the quotient is 4. But this quotient may be too large. To test it, find the volume of Fig. 3, considerine: 4 ft. as the thickness. Thus, 3 x 70' x 4 + 3 x 70 x 4' + 4^ = 62224. Hence, 4 ft. is the triiie thickness, and 74 ft. the length of the edge of a cube whose volume is 405234 cu. ft.
258 evolution: If the cube root contains more than two figures, it may be found by a similar process, as in tlje following example, where it will be seen that the partial divisor at each step is equal to three times the square of that part of the root already found.
What to read after Fish's Arithmetic Number Two : Oral And Written, Upon the Inductive Method 2?
You can find similar books in the "Read Also" column, or choose other free books by Daniel W Fish to read onlineMoreLess
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