Graphics for Engineers, Architects, And Builders: a Manual for Designers ... 2

Cover Graphics for Engineers, Architects, And Builders: a Manual for Designers ... 2
Graphics for Engineers, Architects, And Builders: a Manual for Designers ... 2
Charles E Charles Ezra Greene
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(Multiply 2d equation by 3.6.) 860 yi -f 1080 y, -f 180 y, = 3.6 Q. (Subtract Ist and 3d equations.) 030 ys =3.6Q — P — R.
_ 3.6Q — P — R ^* "~ 930 Substitute in first equation, and find y^i then in third, and find y,.
126. Positive Pier Moment — If the reader will take the trouble to make a numerical solution of this example with the given intensities and distribution of the load as shown in Fig.
66, he will meet with one peculiar result, — the value of y^ will be found to be minus ; that is,
...D' I must be measured off from D' upwards, and denotes a positive bending moment, the truss being concave upwards. There is, therefore, no point of contra- flexure in the span D E, and no negative moment over the pier D. The truss presses on the pier D, however, to an amount to Digitized by VjOOQIC BRIDGE-TEU3SES. 139 be found presently. That this pressure is small arises from the fact that the load on the hundred-foot span has a teriency to lift the truss from D, and it will be seen that almost all of C D is under a negative bending moment.

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