Light a Textbook for Students Who Have Had One Year of Physics
Light a Textbook for Students Who Have Had One Year of Physics
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In our eReader you can find the full English version of the book. Read Light a Textbook for Students Who Have Had One Year of Physics Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Light a Textbook for Students Who Have Had One Year of Physics
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Question (a) is easily answered, for the fish would see his own reflected image, and we only need to apply equation (4) as if the glass wall were non-existent, since its thinness pre- vents it from affecting the problem to any extent. Then we must put r = 50, u = 60, giving v = 42. 9cm. Therefore the fish would see, reflected from the farthest part of the boundary of the globe, an image of himself 42. 9cm. From the boundary, 17. 1 cm. From himself. (If we had tried to find the location of the i...mage of the fish formed by reflection in the nearest part of the wall, it would have come out to be behind the fish and therefore not discernable by him as an image).
To answer question (b), we must apply equation (6), for we have to do with refracted light. Since the light passes from water to air, the appropriate index of refraction is not %, but the reciprocal of this, %. Therefore 31 1 4v' 60- "4X50 Giving v' = 64. 3. Therefore the person outside the globe would see the fish apparently 4. 3 cm farther away than it really is.
What to read after Light a Textbook for Students Who Have Had One Year of Physics?
You can find similar books in the "Read Also" column, or choose other free books by H M Herbert Meredith Reese to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Question (a) is easily answered, for the fish would see his own reflected image, and we only need to apply equation (4) as if the glass wall were non-existent, since its thinness pre- vents it from affecting the problem to any extent. Then we must put r = 50, u = 60, giving v = 42. 9cm. Therefore the fish would see, reflected from the farthest part of the boundary of the globe, an image of himself 42. 9cm. From the boundary, 17. 1 cm. From himself. (If we had tried to find the location of the i...mage of the fish formed by reflection in the nearest part of the wall, it would have come out to be behind the fish and therefore not discernable by him as an image).
To answer question (b), we must apply equation (6), for we have to do with refracted light. Since the light passes from water to air, the appropriate index of refraction is not %, but the reciprocal of this, %. Therefore 31 1 4v' 60- "4X50 Giving v' = 64. 3. Therefore the person outside the globe would see the fish apparently 4. 3 cm farther away than it really is.
What to read after Light a Textbook for Students Who Have Had One Year of Physics?
You can find similar books in the "Read Also" column, or choose other free books by H M Herbert Meredith Reese to read onlineMoreLess
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