Mechanics of Air Machinery
Mechanics of Air Machinery
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To quickly assess the difficulty of the text, read a short excerpt:
m.
[17.65 cu. ft.] per second, we obtain for the radius of the suction orifice = NlS=NlS=«-125m.[4.92ins.].
If we assume the inner radius r^ of the wheel equal to 1.2ro, we have ri= 1.2X0.125 = 0.15 m. [5.9 ins.].
Provided the vanes end radially at the outer circumference of the fan, we now have for the velocity of the outer periphery the value given by equation (8**), ^.==\Ji g,{h+z)^-'^ To determine the values z and w in this expression, let us assume that the fan has an efficiency of 30 per ...cent.; we can then place h 2g€ = 0.30, from which comes From this we obtain Igsh 19.81X800X0.2 __ . ,... ,^- § 27] THE MOVING OF AIR. 157 Now if we assume the outer radius of the wheel to be r, = 0.5 m. [19.69 ins.], the number of R.P.M. is given by n=^,>
What to read after Mechanics of Air Machinery?
You can find similar books in the "Read Also" column, or choose other free books by Julius Ludwig Weisbach to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
m.
[17.65 cu. ft.] per second, we obtain for the radius of the suction orifice = NlS=NlS=«-125m.[4.92ins.].
If we assume the inner radius r^ of the wheel equal to 1.2ro, we have ri= 1.2X0.125 = 0.15 m. [5.9 ins.].
Provided the vanes end radially at the outer circumference of the fan, we now have for the velocity of the outer periphery the value given by equation (8**), ^.==\Ji g,{h+z)^-'^ To determine the values z and w in this expression, let us assume that the fan has an efficiency of 30 per ...cent.; we can then place h 2g€ = 0.30, from which comes From this we obtain Igsh 19.81X800X0.2 __ . ,... ,^- § 27] THE MOVING OF AIR. 157 Now if we assume the outer radius of the wheel to be r, = 0.5 m. [19.69 ins.], the number of R.P.M. is given by n=^,>
What to read after Mechanics of Air Machinery?
You can find similar books in the "Read Also" column, or choose other free books by Julius Ludwig Weisbach to read onlineMoreLess
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