Merchant Vessels
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In our eReader you can find the full English version of the book. Read Merchant Vessels Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Merchant Vessels
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To quickly assess the difficulty of the text, read a short excerpt:
The ist and I7th areas are multiplied by i, every other odd-numbered area by 2 and every even-numbered area by 4, giving the result in the table below.
The length of the vessel may be assumed to be 400 feet, and its division into 16 equal parts makes the common interval between the division points 25 feet. One-third of this common interval is 8% feet. Multiplying the product obtained above by one-third of the common interval we get S l /s X 37> 2 8o = 310, 542 cubic feet GROSS TONNAGE 185 Secti...on Area Multiplier Product Ci I o C2 380 4 1520 C3 680 2 1360 C 4 890 4 356o C5 IOOO 2 2OOO C6 1080 4 4320 C7 II2O 2 2240 C8 1160 4 4640 C9 1160 2 2320 Cio 1080 4 4320 Cn IOOO 2 2OOO Cl2 900 4 3600 Ci3 750 2 1500 Ci 4 575 4 2300 Ci5 400 2 800 Ci6 200 4 800 Ci7 o I o 37280 as the principal volume of the vessel. Since the Moorsom ton is equivalent to 100 cubic feet of space, the tonnage under the tonnage deck of this vessel is about 3105. - This is the register tonnage of the vessel subject to certain later additions and deduc- tions, which in this particular vessel* are extensive.
What to read after Merchant Vessels?
You can find similar books in the "Read Also" column, or choose other free books by Robert Riegel to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
The ist and I7th areas are multiplied by i, every other odd-numbered area by 2 and every even-numbered area by 4, giving the result in the table below.
The length of the vessel may be assumed to be 400 feet, and its division into 16 equal parts makes the common interval between the division points 25 feet. One-third of this common interval is 8% feet. Multiplying the product obtained above by one-third of the common interval we get S l /s X 37> 2 8o = 310, 542 cubic feet GROSS TONNAGE 185 Secti...on Area Multiplier Product Ci I o C2 380 4 1520 C3 680 2 1360 C 4 890 4 356o C5 IOOO 2 2OOO C6 1080 4 4320 C7 II2O 2 2240 C8 1160 4 4640 C9 1160 2 2320 Cio 1080 4 4320 Cn IOOO 2 2OOO Cl2 900 4 3600 Ci3 750 2 1500 Ci 4 575 4 2300 Ci5 400 2 800 Ci6 200 4 800 Ci7 o I o 37280 as the principal volume of the vessel. Since the Moorsom ton is equivalent to 100 cubic feet of space, the tonnage under the tonnage deck of this vessel is about 3105. - This is the register tonnage of the vessel subject to certain later additions and deduc- tions, which in this particular vessel* are extensive.
What to read after Merchant Vessels?
You can find similar books in the "Read Also" column, or choose other free books by Robert Riegel to read onlineMoreLess
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