Navigation And Nautical Astronomy
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L. sid. t. 6 23 43 ■ • • • . L an i 9.73370 —S, —11 6 18 — Red.forG.m.t. —1 20 L. m. t. Sept. 7 18 16 6 Long. — 10 11 49 = 1B2° 67' E.
4. 1865, Sept. 30, in lat 30° 27' N., the Chro. time of the setting of the sun's centre was ll"" 16"" 6«; the Chro. cor., + 15" 25"; height of eye 16 feet; required the local time.
HOUR-ANGLE AND LOCAL TIME, 135 T. by Chro. 11 16 6* Chro. cor. + 16 25 O's. dee.
— 2 64 31.9 Eq'n of i.
—58.30 —10 4.40- -0.801 G. m. t. Sept 30 11 31 31 1 — 11 11.9 H [ 641.3 29.1 -9....23- : or .40 11.625 — 3 544 1 h = — 0S1 [ 1-8 —10 13.6 1 [ 2 Z= 30 27 1. sec 0.06446 p= 93 6 L cosec 0.00064 2 s = 122 56 s= 6128 1. cos 9.67913 ( — A= 62 5 1. sin 9.94627 L. ap. t. Sept. SO 5 "e 34 19.69050 1. sin } 9.84525 Eq. of t — 10 14 • L. m. t Sept 30 5 45 20 Long. + 6'' 30" 46" = 82° 41'i W.
139. Problem 44. To find ike hour-angle of a heavenly body when nearest to, or on, the prime vertical of a given place.
Solution. If > X, and with the same name, as for the body whose diarnal path is n n' (Fig.
What to read after Navigation And Nautical Astronomy?
You can find similar books in the "Read Also" column, or choose other free books by Coffin, J. H. C. (John Huntington Crane), 1815-1890 to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
L. sid. t. 6 23 43 ■ • • • . L an i 9.73370 —S, —11 6 18 — Red.forG.m.t. —1 20 L. m. t. Sept. 7 18 16 6 Long. — 10 11 49 = 1B2° 67' E.
4. 1865, Sept. 30, in lat 30° 27' N., the Chro. time of the setting of the sun's centre was ll"" 16"" 6«; the Chro. cor., + 15" 25"; height of eye 16 feet; required the local time.
HOUR-ANGLE AND LOCAL TIME, 135 T. by Chro. 11 16 6* Chro. cor. + 16 25 O's. dee.
— 2 64 31.9 Eq'n of i.
—58.30 —10 4.40- -0.801 G. m. t. Sept 30 11 31 31 1 — 11 11.9 H [ 641.3 29.1 -9....23- : or .40 11.625 — 3 544 1 h = — 0S1 [ 1-8 —10 13.6 1 [ 2 Z= 30 27 1. sec 0.06446 p= 93 6 L cosec 0.00064 2 s = 122 56 s= 6128 1. cos 9.67913 ( — A= 62 5 1. sin 9.94627 L. ap. t. Sept. SO 5 "e 34 19.69050 1. sin } 9.84525 Eq. of t — 10 14 • L. m. t Sept 30 5 45 20 Long. + 6'' 30" 46" = 82° 41'i W.
139. Problem 44. To find ike hour-angle of a heavenly body when nearest to, or on, the prime vertical of a given place.
Solution. If > X, and with the same name, as for the body whose diarnal path is n n' (Fig.
What to read after Navigation And Nautical Astronomy?
You can find similar books in the "Read Also" column, or choose other free books by Coffin, J. H. C. (John Huntington Crane), 1815-1890 to read onlineMoreLess
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