New Plane And Spherical Trigonometry, Surveying, And Navigation

Cover New Plane And Spherical Trigonometry, Surveying, And Navigation
New Plane And Spherical Trigonometry, Surveying, And Navigation
George Albert Wentworth
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.*. 1 — cote tan 6= 1 — cos-4 = 2sin2^^.
.-. sin (c — 6) = 2 sin2 i -4 cos 6 sin c.
38. If, in a right triangle, p de- note the arc of the great circle passing through the vertex of the right angle and perpendicular to the hypotenuse, m and n the segments 256 SPHEBICAL TBIGONOHETRT.
of the hypotenuse made by this arc adjacent to the legs a and 6, prove that (i.) tan^ = tan c tan m.
(ii.) sin^ = tan m tan n.
(i.) In triangle BCA coaB= tan a cote.
cosB .-. tan a = - -— • cote In right triangle CB
...D coBB = tasiBDcotBC = tanm cot a.
tanm . tana = cos B Multiplying the two equations, ^ _ tanm ^ cosB tan% = ^ X cos 5 cote = tanm tane.
(ii.) In triangle CBD sin p = tan m cot BCD ; and in triangle CAD sin p = tan n cot DC A.
But, since BCD + DC A = 90°, cot BCD X cot DC^ = 1.
.*. sin^ = tan m tan n.
Exercise XXXIII. Page 149.
1. In an isosceles spherical tri- angle, given the base b and the side a ; find A the angle at the base, B the angle at the vertex, and h the altitude.
Let ABA' be an isosceles triangle, A and A' being the equal angles, a and a' the equal sides.


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