On the Spacefilling Curve Heuristic for the Eculidean Traveling Salesman Problem

Cover On the Spacefilling Curve Heuristic for the Eculidean Traveling Salesman Problem
On the Spacefilling Curve Heuristic for the Eculidean Traveling Salesman Problem
Dimitris Bertsimas
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Hence a A b k _ 2 +a fc _i/2 + J12 +J23 = (afc_2 + a*-i)/2 + . 7i2 + j 2A where j 12 is the length of the jump from the last point in T] to the first point in T 2 . And j 2 3 is the length of the jump from the last point in T 2 to the first point in T 3 . To estimate these jump lengths we need to know the first and last points of S'n visited in each subtriangle.
Lemma 2. 2 For n = 2 k, k > 1, the first point in S n (and by similarity S' n ) under order is (xi, yi), and the last point is (
...x p, y p ) where p = (n/2) + 1.
Figure 2: The set 5i 6 in the unit triangle T decomposes into a copy of S' 4 in 7\, a reversed copy of S' 4 in T 2, and a reversed copy of Sg in T 3 . Curve visits the leftmost point first and the ninth point last (marked by arrowheads).
Proof: Let the points of S n be indexed as in the definition (1). By inspection for k 3, we again use figure 2. The first point of S n in T is the first point in T\. The points in S n f] Ji are {(z t, ?/, ), 1

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