On the Spacefilling Curve Heuristic for the Eculidean Traveling Salesman Problem
On the Spacefilling Curve Heuristic for the Eculidean Traveling Salesman Problem
Dimitris Bertsimas
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Hence a A b k _ 2 +a fc _i/2 + J12 +J23 = (afc_2 + a*-i)/2 + . 7i2 + j 2A where j 12 is the length of the jump from the last point in T] to the first point in T 2 . And j 2 3 is the length of the jump from the last point in T 2 to the first point in T 3 . To estimate these jump lengths we need to know the first and last points of S'n visited in each subtriangle. Lemma 2. 2 For n = 2 k, k > 1, the first point in S n (and by similarity S' n ) under order is (xi, yi), and the last point is (...x p, y p ) where p = (n/2) + 1. Figure 2: The set 5i 6 in the unit triangle T decomposes into a copy of S' 4 in 7\, a reversed copy of S' 4 in T 2, and a reversed copy of Sg in T 3 . Curve visits the leftmost point first and the ninth point last (marked by arrowheads). Proof: Let the points of S n be indexed as in the definition (1). By inspection for k 3, we again use figure 2. The first point of S n in T is the first point in T\. The points in S n f] Ji are {(z t, ?/, ), 1
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