Plane And Spherical Trigonometry, And Surveying
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To quickly assess the difficulty of the text, read a short excerpt:
Solve the quadrantal triangle whose sides are : a = 174° 12^ 49.1^^ b= 94° 8^20'^, c = 90°.
128 TRIGONOMETRY.
Let A^, B^, C, a\ ¥, c' repre- sent the corresponding angles and sides of the polar triangle.
Then A'^ 5=> 47^ 10.9^^, B'= 85° bV W\ C^= 90°.
tan^ \ c' = - cos {B'+A') sec {B^-A').
B'+ A^= 91° 38^ 50.9^^ B^- A^= 80° 4^ 29. F^.
log cos (5^+ J-O =8.45863 log sec (^^- .40 = 0.76356 2 )9.22219 log tan Jc^ = 9.61110 Jc^= 22° 12^561^^.
c^ = 44° 25^ 53^^.
C==135°34^ 7^^ tan2 J b'= tan [J {B'+ ...A^ - 45°] tan[45°+H^^-^0]- J (^^+ .SO - 45° = 49^ 25.5^^ 45° + i {B'- A^) = 85° 2^ 14.6^^ log tan 0° 49^ 25.5^^= 8.15770 log tan 85° 2^4.6^^= 11.06133 2) 9.21903 log tan 1 6^= 9.60952 J&^= 22° 8^35^^ 6^= 44° 17^ 10^^.
5 =135° 42^ 50^^ tan2 J a'= tan [J (^^+ ^0 - 45°] tan[45°-H^'-^0]- H-S^+^0 - 45° = 0° 49^ 25.5^^.
45° - J {B'-A') = 4° 57^ 45.4^^ log tan 0° 49^ 25.5^^= 8.15770 log tan 4° 57^ 45.4^/= 8.93867 2 ) 7.0963 7 log tan ^a^= 8.54819 ia^= 2° 1^25^''.
a^= 4° 2^50^^.
What to read after Plane And Spherical Trigonometry, And Surveying?
You can find similar books in the "Read Also" column, or choose other free books by George Albert Wentworth to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Solve the quadrantal triangle whose sides are : a = 174° 12^ 49.1^^ b= 94° 8^20'^, c = 90°.
128 TRIGONOMETRY.
Let A^, B^, C, a\ ¥, c' repre- sent the corresponding angles and sides of the polar triangle.
Then A'^ 5=> 47^ 10.9^^, B'= 85° bV W\ C^= 90°.
tan^ \ c' = - cos {B'+A') sec {B^-A').
B'+ A^= 91° 38^ 50.9^^ B^- A^= 80° 4^ 29. F^.
log cos (5^+ J-O =8.45863 log sec (^^- .40 = 0.76356 2 )9.22219 log tan Jc^ = 9.61110 Jc^= 22° 12^561^^.
c^ = 44° 25^ 53^^.
C==135°34^ 7^^ tan2 J b'= tan [J {B'+ ...A^ - 45°] tan[45°+H^^-^0]- J (^^+ .SO - 45° = 49^ 25.5^^ 45° + i {B'- A^) = 85° 2^ 14.6^^ log tan 0° 49^ 25.5^^= 8.15770 log tan 85° 2^4.6^^= 11.06133 2) 9.21903 log tan 1 6^= 9.60952 J&^= 22° 8^35^^ 6^= 44° 17^ 10^^.
5 =135° 42^ 50^^ tan2 J a'= tan [J (^^+ ^0 - 45°] tan[45°-H^'-^0]- H-S^+^0 - 45° = 0° 49^ 25.5^^.
45° - J {B'-A') = 4° 57^ 45.4^^ log tan 0° 49^ 25.5^^= 8.15770 log tan 4° 57^ 45.4^/= 8.93867 2 ) 7.0963 7 log tan ^a^= 8.54819 ia^= 2° 1^25^''.
a^= 4° 2^50^^.
What to read after Plane And Spherical Trigonometry, And Surveying?
You can find similar books in the "Read Also" column, or choose other free books by George Albert Wentworth to read onlineMoreLess
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