Practical Electrical Testing in Physics And Electrical Engineering: Being a ...
Practical Electrical Testing in Physics And Electrical Engineering: Being a ...
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the total work done against H = Hw(AC + DB) But AC = DB = OA - OC = /- /cos 0" = /(i - cos 0") :, total work done = Hw(AC 4- DB) = H;//2/(i - cos ^°) = HM(i - cos 0) where M = 2lm, the magnetic moment of the needle.
Again, if any body or mass is rotating round a fixed axis, the sum of all the products obtained by multiplying the mass of each particle m in the body by the square of its radius r from that axis, is termed the moment of ina'tia I about the axis, or I = ^mr^.
If, now, G = the galvan...ometer constant, which depends on the form of its coils, etc., then the moment of the force on the needle produced by the current A is = MGA ; and if the current flows for a short time ///, then moment of force = MGA^/ = VlOdg where dq = the small quantity which flows in the time dt; hence the total impulse on the needle = MGQ where Q = the whole quantity that passed in the discharge.
But this impulse is equal to the moment of momentum Iw of the needle, where w = the angular velocity of needle ; /.
What to read after Practical Electrical Testing in Physics And Electrical Engineering: Being a ...?
You can find similar books in the "Read Also" column, or choose other free books by George Dudley Aspinall Parr to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
the total work done against H = Hw(AC + DB) But AC = DB = OA - OC = /- /cos 0" = /(i - cos 0") :, total work done = Hw(AC 4- DB) = H;//2/(i - cos ^°) = HM(i - cos 0) where M = 2lm, the magnetic moment of the needle.
Again, if any body or mass is rotating round a fixed axis, the sum of all the products obtained by multiplying the mass of each particle m in the body by the square of its radius r from that axis, is termed the moment of ina'tia I about the axis, or I = ^mr^.
If, now, G = the galvan...ometer constant, which depends on the form of its coils, etc., then the moment of the force on the needle produced by the current A is = MGA ; and if the current flows for a short time ///, then moment of force = MGA^/ = VlOdg where dq = the small quantity which flows in the time dt; hence the total impulse on the needle = MGQ where Q = the whole quantity that passed in the discharge.
But this impulse is equal to the moment of momentum Iw of the needle, where w = the angular velocity of needle ; /.
What to read after Practical Electrical Testing in Physics And Electrical Engineering: Being a ...?
You can find similar books in the "Read Also" column, or choose other free books by George Dudley Aspinall Parr to read onlineMoreLess
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