Practical Hydrostatics And Hydrostatic Formulas

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Practical Hydrostatics And Hydrostatic Formulas
E Sherman Edward Sherman Gould
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We have therefore: Wx AB^g" T" The pressure, TF', upon the lower sup- port, -4, may be found by subtracting W from T'\ since the whole weight is divided between the two, or it may be found independently in th.e same way as TF. Thus, T" acting with the lever arm AB — g" tends to produce rotation around the upper support B. The tend- ency is resisted by the reaction, W\ of the lower support A^ multiplied by the lever arm A B. . Hence: 87 Example. — ^With the previous data, and letting A B = 11 ii...,^ find the pres- sure upon A and B, Note. — Owing to uncertainty as to exact points of bearing, the distance AB is taken from out to out of the supports.
Solution, — Using formula (24), the pressure, TF, upon the upper support B'\^\ 27562.50 n = 17 W= 1621.32 lbs. Ans.
That on the lower support, A, is: _ 4500 (17 -6.125) 17 TF' = 2878.68 lbs. Ans.
2878.68 4- 1621.32 = 4500 lbs.
All of the values obtained in the pre- ceding series of examples are per run- 88 ning foot. To obtain total pressures, they must be multiplied by the length, or breadth, of the piece undergoing the pressure.


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