Principles of Theoretical Chemistry With Special Reference to the Constitution
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If we replace three hydrogen atoms of methyl alcohol by hydrocarbon residues, alcohols are obtained which contain neither the group CH 2 . OH, nor the group CH. OH, as may be seen in the following examples: H CH 3 C. H 5 H C H, CH 3 C H, CH 3 C H .
I I I H CH, CH 3 Methyl alcohol. Tertiary butyl alcohol. Tertiary amyl alcohol.
These bodies contain the group C. OH, and are repre- sentatives of tertiary alcohols.
The simplest example of this class of alcohols is ter- tiary butyl alcohol, C 4 H 10... O, the constitution of which is indicated by the formula given above.
Proofs The proofs for the correctness of this formula are the following: There is a hydrocarbon, the formula of which can be OH.
shown to be CH 3 C CH 3 . From this, two alco- H hols are derived, one of which conducts itself as a primary GENERAL CONSIDERATIONS. 133 alcohol, and the other of which does not. The former CH 3 must have the formula CH 3 C CH 2 OH . The J.
only alcohol derived from this hydrocarbon which is not a primary alcohol must have the formula CH 3 CH 3 C CH 3, and hence contains the group O I H OH, which is trivalent Further, similar con- i siderations of other tertiary alcohols indicate that in them also the group C.
What to read after Principles of Theoretical Chemistry With Special Reference to the Constitution?
You can find similar books in the "Read Also" column, or choose other free books by Ira Remsen to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
If we replace three hydrogen atoms of methyl alcohol by hydrocarbon residues, alcohols are obtained which contain neither the group CH 2 . OH, nor the group CH. OH, as may be seen in the following examples: H CH 3 C. H 5 H C H, CH 3 C H, CH 3 C H .
I I I H CH, CH 3 Methyl alcohol. Tertiary butyl alcohol. Tertiary amyl alcohol.
These bodies contain the group C. OH, and are repre- sentatives of tertiary alcohols.
The simplest example of this class of alcohols is ter- tiary butyl alcohol, C 4 H 10... O, the constitution of which is indicated by the formula given above.
Proofs The proofs for the correctness of this formula are the following: There is a hydrocarbon, the formula of which can be OH.
shown to be CH 3 C CH 3 . From this, two alco- H hols are derived, one of which conducts itself as a primary GENERAL CONSIDERATIONS. 133 alcohol, and the other of which does not. The former CH 3 must have the formula CH 3 C CH 2 OH . The J.
only alcohol derived from this hydrocarbon which is not a primary alcohol must have the formula CH 3 CH 3 C CH 3, and hence contains the group O I H OH, which is trivalent Further, similar con- i siderations of other tertiary alcohols indicate that in them also the group C.
What to read after Principles of Theoretical Chemistry With Special Reference to the Constitution?
You can find similar books in the "Read Also" column, or choose other free books by Ira Remsen to read onlineMoreLess
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