Problems in the Mathematical Theory of Investment
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In our eReader you can find the full English version of the book. Read Problems in the Mathematical Theory of Investment Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Problems in the Mathematical Theory of Investment
What reading level is Problems in the Mathematical Theory of Investment book?
To quickly assess the difficulty of the text, read a short excerpt:
How much can one afford to expend on a piece of equipment which must be replaced at a cost of flOO every three years for an unlimited time, in order to get better equip- ment which will need replacement only every five years ?
Assume money steadily worth 4%.
Let X = the cost of the better article.
Then we have to compare $100 every three years in x every five years in perpetuity. perpetuity.
To compare two plans we must find the value of each at the same time, in this case preferably at the pre...sent. Since here we must add the cost of first installation to the present value of the perpetuity, this is equivalent to finding the capitalized cost of each article. These plans will be equivalent in the long run if their capitalized costs are equal. This gives the equation of value 100 1 a: 1 . . ^ ■ ■:o4-^=:o4-^'^*^%' whence x = 100 — a-. = 160.42.
One can therefore afford to expend x — 100 = 60.42 for the improvement of the piece of equipment in order to make it last five years instead of three.
What to read after Problems in the Mathematical Theory of Investment?
You can find similar books in the "Read Also" column, or choose other free books by Clements, Guy Roger, 1885- to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
How much can one afford to expend on a piece of equipment which must be replaced at a cost of flOO every three years for an unlimited time, in order to get better equip- ment which will need replacement only every five years ?
Assume money steadily worth 4%.
Let X = the cost of the better article.
Then we have to compare $100 every three years in x every five years in perpetuity. perpetuity.
To compare two plans we must find the value of each at the same time, in this case preferably at the pre...sent. Since here we must add the cost of first installation to the present value of the perpetuity, this is equivalent to finding the capitalized cost of each article. These plans will be equivalent in the long run if their capitalized costs are equal. This gives the equation of value 100 1 a: 1 . . ^ ■ ■:o4-^=:o4-^'^*^%' whence x = 100 — a-. = 160.42.
One can therefore afford to expend x — 100 = 60.42 for the improvement of the piece of equipment in order to make it last five years instead of three.
What to read after Problems in the Mathematical Theory of Investment?
You can find similar books in the "Read Also" column, or choose other free books by Clements, Guy Roger, 1885- to read onlineMoreLess
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