Revolving Vectors With Special Application to Alternating Current Phenomena
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In our eReader you can find the full English version of the book. Read Revolving Vectors With Special Application to Alternating Current Phenomena Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Revolving Vectors With Special Application to Alternating Current Phenomena
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As an example of the former, suppose a circuit, of resistance R and reactance Leo, includes two electromotive forces in series, the second lagging behind the first by a phase difference 6. It is assumed that the frequency is the same for both. The combined e. M. F. Expressed in a uniform circular formula is E = E! + E 2 = fi *% + *- E 2 = e'**[Ei + e ~ ' %] = ' w [#i + (cos 0-/sin 0)E 2 ], = e'^Ei +E 2 cos 0-jE 2 sin 0]. Let us assume that tan 6 f = 2 z, and derive corre- HARMONIC ELECTROMOTIVE... FORCES IN SERIES 31 spending values for sin Q' and cos 6' '. We then shall have 0' /sin 6' cos and cos, cos . The impedance of the circuit is R +jLa), and it produces a lag 6" in the current behind the combined e. M. F. The value of 6" is tan" 1 -^. We have also the relation H R + jLu) = J e "VR 2 + L 2 aj 2 . Therefore the current is 7= E Example. Assume ^i = 1000 volts, ^2 = 1200 volts, 6> = 60, R=12 ohms, Lw = 5 ohms, to find 6', 6", I, and E. Answers. 6' = i&ir l 0. 6495, 0" = tan" 1 -ft, 7= 146.
What to read after Revolving Vectors With Special Application to Alternating Current Phenomena?
You can find similar books in the "Read Also" column, or choose other free books by George Washington Patterson to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
As an example of the former, suppose a circuit, of resistance R and reactance Leo, includes two electromotive forces in series, the second lagging behind the first by a phase difference 6. It is assumed that the frequency is the same for both. The combined e. M. F. Expressed in a uniform circular formula is E = E! + E 2 = fi *% + *- E 2 = e'**[Ei + e ~ ' %] = ' w [#i + (cos 0-/sin 0)E 2 ], = e'^Ei +E 2 cos 0-jE 2 sin 0]. Let us assume that tan 6 f = 2 z, and derive corre- HARMONIC ELECTROMOTIVE... FORCES IN SERIES 31 spending values for sin Q' and cos 6' '. We then shall have 0' /sin 6' cos and cos, cos . The impedance of the circuit is R +jLa), and it produces a lag 6" in the current behind the combined e. M. F. The value of 6" is tan" 1 -^. We have also the relation H R + jLu) = J e "VR 2 + L 2 aj 2 . Therefore the current is 7= E Example. Assume ^i = 1000 volts, ^2 = 1200 volts, 6> = 60, R=12 ohms, Lw = 5 ohms, to find 6', 6", I, and E. Answers. 6' = i&ir l 0. 6495, 0" = tan" 1 -ft, 7= 146.
What to read after Revolving Vectors With Special Application to Alternating Current Phenomena?
You can find similar books in the "Read Also" column, or choose other free books by George Washington Patterson to read onlineMoreLess
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