Solution of Railroad Problems By the Slide Rule

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Solution of Railroad Problems By the Slide Rule
Edward Richard Cary
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11 and ending new curve directly opposite old P.T. in a new parallel tangent 13 feet further from the center, find new degree of curve and new stations of the P.C. and the P.T.
db, Google SIMPLE CURVES 27 #' = R - ^L- = 1635 tan f I tan I 13 ~ tan 11° 12' tan 22° 24' = 1635 ~ 159 ' R' = 1476 feet.
13 Setting for tanll012 , tan22024/ is: Oppo- site 13 on the D scale set 11° 12' on the T scale of the slide reversed, bring the runner to the right index of the T scale, bring 22° 24' on the T scale
...under the runner and opposite the left index of the T scale read 159 on the D scale.
D , = 100_X|438 = 233/==3O53 , T , 22° 24' 1344 . „ = 3°53 / = "233 = stations.
AA' = (R - R') tan £ J + -?—.
sin/ 13 = 159 tan 11° 12' sin 22° 24' = 31.5 + 34.1 = 65.6 feet.
Old P.O. at 126 + 40 65.6 New P.O. at 127+ 5.6 U = 5 + 78 New P.T. at 132 + 83.6 Digitized byr G00gk 28 THE SLIDE RULE 14. Other special problems in simple curves may be solved with fair precision by the use of the slide rule. To get good results it is necessary that the angles whose sines are used shall be between 0° and 70°, and those whose cosines are used shall be between 20° and 90°.


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