Steam Charts Also a Table of Theoretical Jet Velocities And the Corrections of
Steam Charts Also a Table of Theoretical Jet Velocities And the Corrections of
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To quickly assess the difficulty of the text, read a short excerpt:
803 (c 2 ) Final total heat = 1209. 3 B. T. U.
(d 2 ) Final volume =23. 7 cu. Ft.
From Plate 8a, for the pressure of 62 pounds and the superheat of 45 we read: The constant pressure external work = 85 B. T. U.
From Plate 8b, for the pressure of 20 pounds and the super- heat of 112 we read: The constant pressure external work = 87 . 3 B. T. U. Then we may obtain: (e) Initial intrinsic heat = 1201 - 85 = 1116 B. T. U.
Final intrinsic heat = 1209. 3 - 87. 3 = 1122 B. T. U.
The heat required to go ...along a constant temperature line is equal to the change hi entropy multiplied by the absolute tem- perature.
Hence for this case (f) Heat required = (1. 803 - 1. 67) (340 + 460) = 106. 4 B. T. U. Given to the steam.
Representing the initial and final states by the subscripts 1 and 2, we then have, from the fundamental equation of thermodynamics: (g) Work done Heat I 2 supplied J "Gam in intrinsic heat = 106. 4 - [1122 - 1116] = 106. 4 - 6 = 100. 4 B. T. U.
NOTE. This problem is of much more importance as a drill in thermodynamics than as a practical question; because it is very difficult to arrange the necessary apparatus to permit steam to expand isother- mally while in the superheated field.
What to read after Steam Charts Also a Table of Theoretical Jet Velocities And the Corrections of?
You can find similar books in the "Read Also" column, or choose other free books by Frank Oakes Ellenwood to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
803 (c 2 ) Final total heat = 1209. 3 B. T. U.
(d 2 ) Final volume =23. 7 cu. Ft.
From Plate 8a, for the pressure of 62 pounds and the superheat of 45 we read: The constant pressure external work = 85 B. T. U.
From Plate 8b, for the pressure of 20 pounds and the super- heat of 112 we read: The constant pressure external work = 87 . 3 B. T. U. Then we may obtain: (e) Initial intrinsic heat = 1201 - 85 = 1116 B. T. U.
Final intrinsic heat = 1209. 3 - 87. 3 = 1122 B. T. U.
The heat required to go ...along a constant temperature line is equal to the change hi entropy multiplied by the absolute tem- perature.
Hence for this case (f) Heat required = (1. 803 - 1. 67) (340 + 460) = 106. 4 B. T. U. Given to the steam.
Representing the initial and final states by the subscripts 1 and 2, we then have, from the fundamental equation of thermodynamics: (g) Work done Heat I 2 supplied J "Gam in intrinsic heat = 106. 4 - [1122 - 1116] = 106. 4 - 6 = 100. 4 B. T. U.
NOTE. This problem is of much more importance as a drill in thermodynamics than as a practical question; because it is very difficult to arrange the necessary apparatus to permit steam to expand isother- mally while in the superheated field.
What to read after Steam Charts Also a Table of Theoretical Jet Velocities And the Corrections of?
You can find similar books in the "Read Also" column, or choose other free books by Frank Oakes Ellenwood to read onlineMoreLess
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