Students Guide in Quantitative Analysis Intended As An Aid to the Study of Fre

Henry Carrington Bolton

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C. C. >= > : a = . 0713 mgms.
14. J J oxygen J And if 100 c. C. Of water under examination required 0. 8 c. C. Of K 2 Mn 2 O 8, we have O. 8X. O/I3X 10 = mgms. Per litre of oxygen required to oxidize organic matter. This gives . 5704 milligrammes and . 5 704 X. 05 831 8 gives grains of oxygen per gallon. See I, Calculation of Results.
I. Calculation of Results.
To convert grms. In a litre \X\\JQ grains in a gallon, multi- ply the number of milligrammes of each constituent by 0. 058318; or use D...r. Waller's Table, published in Am. CJtcm. , Vol. V, p. 278. Report results in two ways : the grains per gallon of uncombined constituents, viz. , SiO 2, Fe 2 O 3, A1 2 O 3, CaO, MgO, Na 2 O, K 2 O, Cl, SO 3, together with " Loss by Ignition " and " Total Solids ; " and secondly 96 QUANTITATIVE ANALYSIS.
report the grains per gallon of the bases combined with acids in accordance with the following scheme.
Combine " " Na as Na 2 SO 4 " excess of Cl " Mg C1 2 " SO 4 " Ca SO 4 " " " Mg " Mg CO 3 " " " Ca " Ca CO 3 " " " K " K 2 SO 4 " K " K Cl " " " Cl " Na Cl The sum of the combined salts -f- " Loss by Ignition " should equal the " Total Solids " very nearly.

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