The Essentials of Geometry

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PROP. X. PROBLEM. 324. To express the area of a triangle in terms of its three sides. C D a B Given sides BC, CA, and AB, of A ABC, equal to a, b, and c, respectively. Required to express area ABC in terms of a, &, and c. Solution. Let (7 be an acute Z, and draw altitude AD. . 2 /-2 I 7)2 9 /7 v /^T") /'S 977\ .. C a -h ^ a x UIA (jj ^< <; Transposing, 2 a x CD = a 2 + 6 2 c 2 . ^^ a 2 + 6 2 - c 2 2a ( 273) = (AC + CD) (AC -CD) - c 2 ) (2 a& - a 2 c 2 ) 4 a 2 5)2_c2][ C 2_( a _5)2] 4 a 2 _ (a + 6 + c) (a + b - c) (c + a - b) (c - a + 6) 4 a 2 Now let a + b + c = 2 s. rr j_2s(2s-2c)(2s-2b)(2s-2 a) ~^T _ 16 s (s a) (s b) (s c) 4 a 2 AREAS OF POLYGONS. 173 ... AD = 2 ^ s ( s - a ) ( s ~ 6 ) ( s ~ c ) a . -. Area ABC = \ a x AD (?) = Vs(s a) (s 6) (s c). 325. Sch. Let it be required to find the area of a tri- angle whose sides are 13, 14, and 15. Let a = 13, b = 14, and c = 15 ; then s = (13 + 14 + 15) = 21. Whence, s a = 8, s 6 = 7, and s c = 6. Then, the area of the triangle is V21x 8 x 7 x 6 = V3 x 7 x 2 3 x 7x2x3 = V2 4 x 3 2 x 7 2 = 2 2 x 3 x 7 = 84.

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