The Field Engineer a Handy book of Practice in the Survey Location And Track
The Field Engineer a Handy book of Practice in the Survey Location And Track
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In our eReader you can find the full English version of the book. Read The Field Engineer a Handy book of Practice in the Survey Location And Track Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book The Field Engineer a Handy book of Practice in the Survey Location And Track
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To quickly assess the difficulty of the text, read a short excerpt:
fore, = 797. 7 feet, say 798 feet, = A B. To find B C, solve the triangle BDC, observing that the angle DBC = B AI = one-half of the central angle 32 20', = 16 10', and that t> C = 00 feet. Then D C -f- nat. *in. 16 10' = 60 -=- . 278 = say 216 feet, = B C. Hence AC = AB-fBC = 798 -f 216 = 1, 014 feet.
Having thus found the length of chord A C, the radius and rate of curvature may be deduced as in X.
Or, dividing the tabular chord of 32 20' by chord A C = 1, 014, the degree of the required curv...e is ascertained directly to be 3. 15, equivalent to 3 09'.
2. SECOND METHOD. Find the apex distance AH, = AI + I H. The tabular tangent of 32 20' divided by 4 gives A I = 415 feet. In the triangle KDC, the side DC -i- nat. Sin. K = 60 -f- nat. Sin. 32 20V = 112 feet = KG = I H. Then AH = A I -f- IH = 415 + 112 = 527 feet; and the tabular tangent 1, 661 -f- 527 gives 3. 15, equivalent to 3 09', the degree of the required curve A C, as before.
XXX.
HAVING LOCATED A CURVE A B C, TO FIND THE POINT B AT WHICH TO COMPOUND INTO ANOTHER CURVE OF GIVEN RADIUS, WHICH SHALL END IN TANGENT E F, PARALLEL TO THE TERMINAL TANGENT OF THE ORIGINAL CURVE, AND A GIVEN DISTANCE FROM IT.
What to read after The Field Engineer a Handy book of Practice in the Survey Location And Track?
You can find similar books in the "Read Also" column, or choose other free books by William Findlay Shunk to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
fore, = 797. 7 feet, say 798 feet, = A B. To find B C, solve the triangle BDC, observing that the angle DBC = B AI = one-half of the central angle 32 20', = 16 10', and that t> C = 00 feet. Then D C -f- nat. *in. 16 10' = 60 -=- . 278 = say 216 feet, = B C. Hence AC = AB-fBC = 798 -f 216 = 1, 014 feet.
Having thus found the length of chord A C, the radius and rate of curvature may be deduced as in X.
Or, dividing the tabular chord of 32 20' by chord A C = 1, 014, the degree of the required curv...e is ascertained directly to be 3. 15, equivalent to 3 09'.
2. SECOND METHOD. Find the apex distance AH, = AI + I H. The tabular tangent of 32 20' divided by 4 gives A I = 415 feet. In the triangle KDC, the side DC -i- nat. Sin. K = 60 -f- nat. Sin. 32 20V = 112 feet = KG = I H. Then AH = A I -f- IH = 415 + 112 = 527 feet; and the tabular tangent 1, 661 -f- 527 gives 3. 15, equivalent to 3 09', the degree of the required curve A C, as before.
XXX.
HAVING LOCATED A CURVE A B C, TO FIND THE POINT B AT WHICH TO COMPOUND INTO ANOTHER CURVE OF GIVEN RADIUS, WHICH SHALL END IN TANGENT E F, PARALLEL TO THE TERMINAL TANGENT OF THE ORIGINAL CURVE, AND A GIVEN DISTANCE FROM IT.
What to read after The Field Engineer a Handy book of Practice in the Survey Location And Track?
You can find similar books in the "Read Also" column, or choose other free books by William Findlay Shunk to read onlineMoreLess
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