The Field of a Dipole Above An Infinite Corrugated Plane
The Field of a Dipole Above An Infinite Corrugated Plane
Ta Shing Chu
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The solution for g may be written down immediately: (3. 3) g = r" >. R n :^2 -[ p ik R' Sh oJM. Sz -I L r' ikR'S where R' = \/x^ + (y - h)^+ z^ fn R - h sin sin (j), R' • =\/ x2 + (y + h)^ + z^ ~ R + h sin 9 sin (j), R = \/x2 + y2 + z^, 9 = tan" ^ -1 y , and (p = tan — x'"+ y"" ^ y3775 We may expect the far-zone radiation field of f to be of the form (3.^) mje^) ikR R Substituting (3. 3) and (3.^) into (3. 1), introducing polar coordinates, and keeping terms of order -x, we obtain fr -1 ■ a ■ ^... X / ? ? 2 flj -ikh sin sin (t) J -ik sm 9 sm
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