The Graphical Solution of Hydraulic Problems. Treating of the Flow of Water Through Pipes, in Channels And Sewers, Over Weirs, Etc.

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long with end contraction and measured head or' 0.6 ft. ?
* The velocity may also be obtained by observations with floats or a current-meter.
RECTANGULAR WEIRS. 43 The channel is 6 ft. wide and 1.5 ft. deep = 9 sq. ft.
area, depth below crest 1 foot.
Corrected s length = 4— {.zh or .12) = 3.88 ft.; the ap- proximate discharge, from diagram No. 23, due to .6 head is 6 cu. ft. per second. Velocity of approach = 6-^9 = 0.667 f eet P er second. On Table No. 6, for weirs with end contraction, opposi
...te v = 0.7, and in column for depth below crest = 1 foot and head of 0.60, find the correction = 0.013 ! a dd this to the measured head, = 0.6 + 0.013 = °-6 I 3- Then, with corrected length = 4 — 2h = 3.877, the discharge for corrected head of 0.613 ~ 6.2 cu. ft. per second or 2780 gallons per minute.
Note. — Fteley and Stearns give a diagram in the paper referred to from which the head to be added for velocity of approach can be taken directly, without first finding the mean Velocity. This diagram only applies to weirs without end contraction.


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