The Solution of the Pyramid Problem; Or, Pyramid Discoveries. With a New Theory As to Their Ancient Use
The Solution of the Pyramid Problem; Or, Pyramid Discoveries. With a New Theory As to Their Ancient Use
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In our eReader you can find the full English version of the book. Read The Solution of the Pyramid Problem; Or, Pyramid Discoveries. With a New Theory As to Their Ancient Use Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book The Solution of the Pyramid Problem; Or, Pyramid Discoveries. With a New Theory As to Their Ancient Use
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Thus — Ratio apothem to half base Mycerinus. 32 to 20 " " " " Cephren ....33 to 20 " " " " Cheops 34 to 2 1 AREA OF THE FOUR SIDES. AREA OF THE BASE.
Mycerinus 70560' 44100 Cephren 291060* 176400 Cheops 33°777'9° 204304 All in R.B. cubits.
Digitized by VjOOQ IC SOLUTION OF THE PYRAMID PROBLEM. 29 32 20 : : 7°5 6 °' : 44100 33 20 : : 291060* : 176400 34 21 : ' 330777*90 : 204304 * Herodotus states that " the area of each of the four faces of Cheops was equal to the area of a square whose base wa...s the altitude of a Pyramid ; " or, in other words, that altitude was a mean proportion^ to apothem and half base ; thus — : area of one face equals the fourth of 330777*90 or 82694*475 R.B. cubits, and the square root of 82694*475 is 287*56. But the correct altitude is 287*77, so the error is 0*21, or \]i British inches. I have therefore the authority of Herodotus to support the theory which I shall subsequently set forth, that this pyramid was the exponent of lines divided in mean and extreme ratio.
What to read after The Solution of the Pyramid Problem; Or, Pyramid Discoveries. With a New Theory As to Their Ancient Use?
You can find similar books in the "Read Also" column, or choose other free books by Robert Ballard to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Thus — Ratio apothem to half base Mycerinus. 32 to 20 " " " " Cephren ....33 to 20 " " " " Cheops 34 to 2 1 AREA OF THE FOUR SIDES. AREA OF THE BASE.
Mycerinus 70560' 44100 Cephren 291060* 176400 Cheops 33°777'9° 204304 All in R.B. cubits.
Digitized by VjOOQ IC SOLUTION OF THE PYRAMID PROBLEM. 29 32 20 : : 7°5 6 °' : 44100 33 20 : : 291060* : 176400 34 21 : ' 330777*90 : 204304 * Herodotus states that " the area of each of the four faces of Cheops was equal to the area of a square whose base wa...s the altitude of a Pyramid ; " or, in other words, that altitude was a mean proportion^ to apothem and half base ; thus — : area of one face equals the fourth of 330777*90 or 82694*475 R.B. cubits, and the square root of 82694*475 is 287*56. But the correct altitude is 287*77, so the error is 0*21, or \]i British inches. I have therefore the authority of Herodotus to support the theory which I shall subsequently set forth, that this pyramid was the exponent of lines divided in mean and extreme ratio.
What to read after The Solution of the Pyramid Problem; Or, Pyramid Discoveries. With a New Theory As to Their Ancient Use?
You can find similar books in the "Read Also" column, or choose other free books by Robert Ballard to read onlineMoreLess
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