The Theory of Electric Cables And Networks
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-. L FIG. 15.
and thus RC=4=p. If the main had been supplied from one end only, the greatest value C' of the current would be given by RC' =p. For the same maximum voltage drop, therefore, we could supply four times as much current when we feed from both ends of the main, but the losses in heating the mains would be sixteen times greater in the latter case.
It sometimes happens that the cross section current of the main found by formula (2) makes the current density too high. In this case, the ...greatest permissible current density is chosen. In only a few cases would it be advisable to choose a current density as high as 2'5 amperes per sq. Mm. (approxi- mately 1, 600 amperes per sq. In. ). Suppose, for 74 ELECTRIC CABLES AND NETWORKS instance, that p is 2, 1=20 metres and %C=30 (Fig. 16). Formula (2) gives =20x30/(30x2)=10 sq. Mms.
M Zo Ao FIG. 16.
This would give a current density of 30/10, that is, 3 amperes per sq. Mm. It would be better, therefore, to make the area of the cross section 15 sq.
What to read after The Theory of Electric Cables And Networks?
You can find similar books in the "Read Also" column, or choose other free books by Alexander Russell to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
-. L FIG. 15.
and thus RC=4=p. If the main had been supplied from one end only, the greatest value C' of the current would be given by RC' =p. For the same maximum voltage drop, therefore, we could supply four times as much current when we feed from both ends of the main, but the losses in heating the mains would be sixteen times greater in the latter case.
It sometimes happens that the cross section current of the main found by formula (2) makes the current density too high. In this case, the ...greatest permissible current density is chosen. In only a few cases would it be advisable to choose a current density as high as 2'5 amperes per sq. Mm. (approxi- mately 1, 600 amperes per sq. In. ). Suppose, for 74 ELECTRIC CABLES AND NETWORKS instance, that p is 2, 1=20 metres and %C=30 (Fig. 16). Formula (2) gives =20x30/(30x2)=10 sq. Mms.
M Zo Ao FIG. 16.
This would give a current density of 30/10, that is, 3 amperes per sq. Mm. It would be better, therefore, to make the area of the cross section 15 sq.
What to read after The Theory of Electric Cables And Networks?
You can find similar books in the "Read Also" column, or choose other free books by Alexander Russell to read onlineMoreLess
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