The Theory of Structures
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In our eReader you can find the full English version of the book. Read The Theory of Structures Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book The Theory of Structures
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Pitch = 4 inches.
2. A cross girder for a bridge carryivy two lines of rails is 27 feet long and 24 inches deep ; ^ it carries four concentrated loads, f \ i^.-.4»...^.J ! ^ a \ each weighing 30 tons ; the two ^ I -^ -^t- ^^ -©J loads on one side of the centre i 1 -^y ^hQ? -©• of span being symmetrical with \ \ ^ "^^ ^ the two on the other side. Deter- ' " ^ig, 115.
mine the pitch of the angle rivets if the diameter of rivet is J inch.
Thickness of web = J inch.
Assume same working stresses as ...in last example.
Eivets in double shear.
Shear strength of one rivet = 2x0-6x6 = 7-2 tons.
Bearing strength of rivet on web plate = | x J x 12 = 5-25 tons.
Least B = 5-25 tons.
Shearing force at ends, F = 2 x 30 = 60 tons.
From (3) ^ 5-25x24 ^ 2-1 inches.
^ 60 This pitch is too small for a single line of rivets.
Therefore we must use angles 4Y x 4^" x Y with two rows of rivets placed zig-zag (Fig. 115).
Now, as there are two rivets in each pitch, m ^ 2x5-25x24 ^ ^.^ .^^j^^^ ^ F 60 Pitch = 4 inches.
What to read after The Theory of Structures?
You can find similar books in the "Read Also" column, or choose other free books by Richard John Woods to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Pitch = 4 inches.
2. A cross girder for a bridge carryivy two lines of rails is 27 feet long and 24 inches deep ; ^ it carries four concentrated loads, f \ i^.-.4»...^.J ! ^ a \ each weighing 30 tons ; the two ^ I -^ -^t- ^^ -©J loads on one side of the centre i 1 -^y ^hQ? -©• of span being symmetrical with \ \ ^ "^^ ^ the two on the other side. Deter- ' " ^ig, 115.
mine the pitch of the angle rivets if the diameter of rivet is J inch.
Thickness of web = J inch.
Assume same working stresses as ...in last example.
Eivets in double shear.
Shear strength of one rivet = 2x0-6x6 = 7-2 tons.
Bearing strength of rivet on web plate = | x J x 12 = 5-25 tons.
Least B = 5-25 tons.
Shearing force at ends, F = 2 x 30 = 60 tons.
From (3) ^ 5-25x24 ^ 2-1 inches.
^ 60 This pitch is too small for a single line of rivets.
Therefore we must use angles 4Y x 4^" x Y with two rows of rivets placed zig-zag (Fig. 115).
Now, as there are two rivets in each pitch, m ^ 2x5-25x24 ^ ^.^ .^^j^^^ ^ F 60 Pitch = 4 inches.
What to read after The Theory of Structures?
You can find similar books in the "Read Also" column, or choose other free books by Richard John Woods to read onlineMoreLess
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