Theoretical Mechanics
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In our eReader you can find the full English version of the book. Read Theoretical Mechanics Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Theoretical Mechanics
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Analysis of (I) is important. If Vq = Sq= 0, then v = ±ft, s==±lft^ v^=±2fs, formulas giving the velocity and distance due to the force only.
To obtain (I) and (II), we add on the initial velocity to get the final velocity, and the distance ( = v^t^ due to it and the initial distance to get the total distance.
i MOTION OF A PARTICLE IN A CONSTANT FIELD 139 ILLUSTRATIVE EXAMPLES 1. Bectilinear motion under gravitation. In this case f — g. We distinguish two problems.
Particle projected verticall...y upwards. Taking the upward direction as positive, and the origin as the point of projection, we have in (I), sq = 0, and obtain (1) V = Vo - gt, s = vot - |- gt^, in which vo is the velocity of projection. The highest point A is reached when V -0. Then t = — , and s = OA = ^. This is therefore the , . , a 2q greatest height.
Particle falling freely. Choosing the downward direction as positive, we obtain from (I), (2) V - vo + gt, s = So + Vot + I gt^.
If the particle falls from rest at the origin, then vo = 0, So = 0, and we get (3) v = gt, s = \gt\ v'^^2gs.
What to read after Theoretical Mechanics?
You can find similar books in the "Read Also" column, or choose other free books by Percey F Percey Franklyn Smith to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Analysis of (I) is important. If Vq = Sq= 0, then v = ±ft, s==±lft^ v^=±2fs, formulas giving the velocity and distance due to the force only.
To obtain (I) and (II), we add on the initial velocity to get the final velocity, and the distance ( = v^t^ due to it and the initial distance to get the total distance.
i MOTION OF A PARTICLE IN A CONSTANT FIELD 139 ILLUSTRATIVE EXAMPLES 1. Bectilinear motion under gravitation. In this case f — g. We distinguish two problems.
Particle projected verticall...y upwards. Taking the upward direction as positive, and the origin as the point of projection, we have in (I), sq = 0, and obtain (1) V = Vo - gt, s = vot - |- gt^, in which vo is the velocity of projection. The highest point A is reached when V -0. Then t = — , and s = OA = ^. This is therefore the , . , a 2q greatest height.
Particle falling freely. Choosing the downward direction as positive, we obtain from (I), (2) V - vo + gt, s = So + Vot + I gt^.
If the particle falls from rest at the origin, then vo = 0, So = 0, and we get (3) v = gt, s = \gt\ v'^^2gs.
What to read after Theoretical Mechanics?
You can find similar books in the "Read Also" column, or choose other free books by Percey F Percey Franklyn Smith to read onlineMoreLess
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