Tight Comparison Bounds On the Complexity of Parallel Sorting
Tight Comparison Bounds On the Complexity of Parallel Sorting
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In our eReader you can find the full English version of the book. Read Tight Comparison Bounds On the Complexity of Parallel Sorting Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Tight Comparison Bounds On the Complexity of Parallel Sorting
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To quickly assess the difficulty of the text, read a short excerpt:
To see this, simply simulate the AKS network by slowing it down to work in k rounds.
For k = \, c(\, n) = ^(n'^-n). This is since any sorting algorithm which works in one round must perform all comparisons. Otherwise, suppose that a dispensed comparison is between two successive elements in the sorted order; the algorithm will clearly fail to distinguish their order. On the other hand, observe that performing all comparisons simultaneously yields an one round algorithm in the parallel compariso...n model that matches exactly this lower bound, i. E. , ui l, /i. ) = %(«"-«).
So, it remains to consider the situation for 1 k( - n) for an V A:, A? > 1, where ^ is the base of the natural logarithm.
e Corollaries of the main result: Suppose we have p processors with the interpretation that each processor can perform at most one comparison at each round. Observed that kp^c{k, n) or p^cik, n)/k . Therefore, Corollary 1.
What to read after Tight Comparison Bounds On the Complexity of Parallel Sorting?
You can find similar books in the "Read Also" column, or choose other free books by Yassi Azar to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
To see this, simply simulate the AKS network by slowing it down to work in k rounds.
For k = \, c(\, n) = ^(n'^-n). This is since any sorting algorithm which works in one round must perform all comparisons. Otherwise, suppose that a dispensed comparison is between two successive elements in the sorted order; the algorithm will clearly fail to distinguish their order. On the other hand, observe that performing all comparisons simultaneously yields an one round algorithm in the parallel compariso...n model that matches exactly this lower bound, i. E. , ui l, /i. ) = %(«"-«).
So, it remains to consider the situation for 1 k( - n) for an V A:, A? > 1, where ^ is the base of the natural logarithm.
e Corollaries of the main result: Suppose we have p processors with the interpretation that each processor can perform at most one comparison at each round. Observed that kp^c{k, n) or p^cik, n)/k . Therefore, Corollary 1.
What to read after Tight Comparison Bounds On the Complexity of Parallel Sorting?
You can find similar books in the "Read Also" column, or choose other free books by Yassi Azar to read onlineMoreLess
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